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3 years ago

Need help with this math

Mathematics

1 answer:

serg [7]3 years ago

5 0

we use the interest formula. 4000*1.03^11=1.38423387*4000=5536.93548, or 5536.94.

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Q.18 - Please help! I will give Brainliest!!!

Ipatiy [6.2K]

ANSWER: x will equal 3 I hope this helps

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3 years ago

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Tom predicted that the Giants what score three point field goal scored two 6 points touchdowns in for one extra points if Tom we

frozen [14]

If they only scored one field goal they would start with 3, and if they scored one extra point on each touchdown that would be 7+7+3 that would equal 17. If they only scored one extra point between two touchdowns than it would be 3+7+6=16

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3 years ago

She leaves a 20% tip of 1.80 what is the price of mira’s breakfast before the tip.

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Answer:

Step-by-step explanation:

The breakfast before tip costs x.

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2 years ago

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Answer:

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Step-by-step explanation:

Zero

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3 years ago

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EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

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3 years ago