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Alex787 [66]
3 years ago
15

Find the value of X.

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
8 0
The sum of three angles have to equal to 180°.
(right angle : 90°)
2x + 15 + 90 + x = 180
3x + 105 = 180

3x = 75

x = 25

so the angles would be
25° , 90° , 65°
nordsb [41]3 years ago
3 0
90+(2x+15)+x=180
90+2x+15+x=180
105+3x=180
3x=75
x=75/3
x=25degree
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Great Granola makes a trail mix consisting of peanuts, cashews, raisins, and dried cranberries. The trail mix sells for $3.50, a
patriot [66]

Answer:

A C D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Simplify the following expression:<br> 9^−53 ⋅ 9^37<br><br> Please also explain your answer. Thanks!
Alexus [3.1K]

Answer: 9^-16

Step-by-step explanation:

a^b*a^c= a^b+c

8 0
3 years ago
Does the point (1, –9) satisfy the equation y = 3x − 6?
Tju [1.3M]

Answer:

No.

Step-by-step explanation:

Well, is the points (1, -9) does satisfy the equation y = 3x - 6. Then, substituting the values of x, and, y, into the equation y = 3x - 6,  we should get a true equation.

y = 3x - 6

-9 = 3 * 1 - 6

-9 = 3 - 6

-9 = -3.

So, the points (1, -9) does not satisfy the equation y = 3x - 6.

8 0
2 years ago
Question in photo—————————-
11111nata11111 [884]

Answer:

there is two solutions to that problem. you can find x is equal to two numbers.

7 0
2 years ago
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