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2 years ago

according to the research how much faster will the fastest dinosaur run in comparison to the t.rex show your math

1 answer:

8 0

Well, according to thedinosaurmuseum.com, the fastest ever running dinosaur(s) could run to up to (approx.) 60 km an hour. And according to sciencenetlinks.com, T. rex's ran approx. 45 miles an hour. To be able to subtract, you would have to find out how many kilometers in a mile. There are 1.60934 kilometers in a mile (round it to 1.6). So that means that a mile is slightly larger than a kilometer. Now you have to multiply 60 km by 1.6. Once you do that, subtract that number by 45. And there is your answer! I hope this has helped!

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Dionne can fold 175 packing boxes in 50 minutes. Elias can fold 120 packing boxes in 40 minutes. Who has the faster folding rate

lapo4ka [179]

Answer:

Dionne :)

Step-by-step explanation:

7 0

2 years ago

Multiply and Simplify (x-4)(x^2 - 5x - 6)

kirill [66]

Answer:

x^3 -9x^2 +14x +24

Step-by-step explanation:

(x-4)(x^2 - 5x - 6)

Multiply the x by everything in the second term

x * (x^2 - 5x - 6)

x^3 -5x^2 -6x

Multiply the -4 by everything in the second term

-4 * (x^2 - 5x - 6)

-4x^2 +20x +24

Add everything together

I like to line them up vertically

x^3 -5x^2 -6x

-4x^2 +20x +24

-------------------------------

x^3 -9x^2 +14x +24

4 0

2 years ago

Read 2 more answers

A pool can be filled by one pipe in 8 hours and by a second pipe in 2 hours. How long will it take using both pipes to fill the

andreev551 [17]

let the time taken to be filled by both pipes be y

1/2 +1/8=1/y

(4+1)/8=1/y

5/8=y

cross multiplying

5y=8

y=8/5

=1.6hrs

7 0

3 years ago

What capital leffer appears to have parallel lines? D or L or N or T?

Liono4ka [1.6K]

Answer:

N, the verticle lines are are parallel

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Properties of exponents Rewrite the expression in the form b^n—— (b^2)^3/7

exis [7]

Answer:

$b^{\frac{6}{7}}$ is the required expression.

Step-by-step explanation:

$(b^2)^{\frac{3}{7}}\\\\\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0\\\\=b^{2\cdot \frac{3}{7}}\\\\=b^{\frac{6}{7}}$

Best Regards!

3 0

3 years ago