Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
So, -15-7=-22
Answer:
Step-by-step explanation:
hello :
let : f(x) this denominator :
12/x(x+4) = f(x)/x(x+4)(x-9)
f(x) =12x(x+4)(x-9)/x(x+4)
if : x(x+4)(x-9)≠0 simpify by : x(x+4)
f(x) = 12(x-9)
Angle AEC and angle AED are angles on a straight line. They are supplementary angles. One is a supplement of the other angle.
<h3>What are Supplementary Angles?</h3>
Two angles are defined as supplementary angles when the sum of both angles are equal to 180 degrees. According to the linear angle pair theorem, if two angles are on a straight line, then the sum of both angle measures would be equal to 180 degrees. Therefore, one is the supplement of the other. In the same vein, angles on a straight line are therefore supplementary angles.
If two angles are on a straight line, the measure of one angle would be the supplement of the other because their sum is equal to 180 degrees.
Angle AEC and angle AED in the diagram given, are angles on a straight line, thus, they are supplementary angles and they have a sum of 180 degrees. One is a supplement of the other angle.
Learn more about supplementary angles on:
brainly.com/question/8992900
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<u>Answer:
</u>
The value of the exponential expression
is 2
<u>Solution:</u>
16 superscript one-fourth= ![16^{\frac{1}{4}}](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
As per the problem,
We have to find the value of
16 in terms of 2 can be written as ![2\times2\times2\times2](https://tex.z-dn.net/?f=2%5Ctimes2%5Ctimes2%5Ctimes2)
= ![(2 \times 2 \times 2 \times 2)^{\frac{1}{4}}](https://tex.z-dn.net/?f=%282%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
=![\left(2^{4}\right)^{\frac{1}{4}}](https://tex.z-dn.net/?f=%5Cleft%282%5E%7B4%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
As per the exponential rule, ![a^{(m)^{n}}=a^{m \times n}](https://tex.z-dn.net/?f=a%5E%7B%28m%29%5E%7Bn%7D%7D%3Da%5E%7Bm%20%5Ctimes%20n%7D)
=![2^{4 \times \frac{1}{4}}](https://tex.z-dn.net/?f=2%5E%7B4%20%5Ctimes%20%5Cfrac%7B1%7D%7B4%7D%7D)
Here, ![4\times\frac{1}{4}=1](https://tex.z-dn.net/?f=4%5Ctimes%5Cfrac%7B1%7D%7B4%7D%3D1)
= ![2^{1}](https://tex.z-dn.net/?f=2%5E%7B1%7D)
= 2
Hence, the value is 2.