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Nat2105 [25]
3 years ago
10

PLEASE LOOK AT THIS multiple choice, thanks.

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer:

The answer should be y= -2x + 8

Step-by-step explanation:

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I can't figure this out
andriy [413]
Suppose that equation of parabola is
y =ax² + bx + c


Since parabola passes through the point (2,−15) then 
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then 
−5 = 9a − 3b + c


Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that 
a = −2, b = −4, c = 1

Thus, equation of parabola is
y = −2x²− 4x + 1

____________________

Rewriting in the form of 
(x - h)² = 4p(y - k)

i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36 

vi) (x + 7/6)² = -⅓(y - 445/36) 
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p) 


So, after rewriting the equation would be - 

(x + 7/6)² = 4(-⅛)(y - 445/36)

__________________

I hope this is what you wanted.

Regards,
Divyanka♪
__________________
6 0
3 years ago
Read 2 more answers
Which postulate or theorem could be used to prove triangleLMQ is congruent to triangleLNP
Sliva [168]

The answer to this query is AA similarity postulate. <span>

<span>Because the triangles given are only similar in angle but dissimilar in sides which makes it incongruent with respect to the sides, AA similarity postulate is the exact answer. 

SAS ASA are not possible answers. </span></span>

6 0
3 years ago
Read 2 more answers
Y=1/2x-1
Alinara [238K]

Answer:

<h2>Y=1/2x-1</h2>

Find where the expression

1/2x−1 is undefined.

x=1/2

Consider the rational function

R(x)=ax^n/bx^m where n is the degree of the numerator and m is the degree of the denominator.

1. If n<m, then the x-axis, y=0, is the horizontal asymptote.

2. If n=m, then the horizontal asymptote is the line y = ab.

3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).

Find n and m.n=0m=1

Since n<m, the x-axis, y=0, is the horizontal asymptote.y=0

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

x=1/2

Horizontal Asymptotes:

y=0

No Oblique Asymptotes

<h2>2x+y=4</h2>

Subtract 2x from both sides of the equation.

y=4−2x

Rewrite in slope-intercept form.

The slope-intercept form is

y=mx+b, where m is the slope and b is the y-intercept.

y=mx+b

Reorder 4 and −2x.

y=−2x+4

Use the slope-intercept form to find the slope and y-intercept.

Find the values of m and b using the form

y=mx+b.

m= - 2b=4

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: −2

y-intercept: (0,4)

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y

values.

Find the x-intercept.

x-intercept(s):

(2,0)

Find the y-intercept.

y-intercept(s):

(0,4)

Create a table of the x and y values.

x y

0 4

2 0

Graph the line using the slope and the y-intercept, or the points.

Slope: −2

y-intercept:

(0,4)

Step-by-step explanation:

Hope it is helpful...

8 0
3 years ago
The total cost for a bucket of popcorn and 4 movie tickets is $56. The total cost for the same size bucket of popcorn and 6
ratelena [41]

Answer:

y = 12x + 8

Step-by-step explanation:

You can come to this conclusion by plugging in the amount of tickets bought as x in each equation, making sure the the answer y is $56 if x = 4 and $80 if x = 6

3 0
2 years ago
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Which figure has exacly 2 sets of parallel sides and no perpendicular sides
sweet-ann [11.9K]
Square. Because there is 2 right angles there are only 4 sides all which are perpendicular
5 0
3 years ago
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