Complete this pattern 3400000, 34000,______3.4,_____

Write an expression equivalent to (6x + 4y) – 2y by combining like terms. Enter the numbers in the boxes

raketka [301]

6x +2y

Solution:

Given expression is (6x + 4y) –2y.

To find the equivalent expression for the given expression.

⇒ (6x + 4y) –2y

⇒ 6x + 4y –2y

Combine like terms together.

⇒ 6x + (4y –2y)

⇒ 6x + 2y

6x +2y is equivalent to (6x + 4y) –2y.

Hence, the expression equivalent to (6x + 4y) –2y is 6x + 2y.

5 0

3 years ago

A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selecti

Andrews [41]

Answer:

(a) Null Hypothesis, $H_0$ : p = 0.50

Alternate Hypothesis, $H_A$ : p > 0.50

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed.

(e) The value of z test statistics is 0.96.

(f) The P-value is 0.1685.

(g) At 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) We conclude that the proportion of baby girls is equal to 0.50.

Step-by-step explanation:

We are given that a 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5.

Assume that sample data consists of 78 girls in 144 births.

Let p = population proportion of baby girls

(a) So, Null Hypothesis, $H_0$ : p = 0.50 {means that the proportion of baby girls is equal to 0.50}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the proportion of baby girls is greater than 0.50}

(b) The value of level of significance (α) given in the question is 0.10.

(c) The sampling distribution of the sample statistic is Normal distribution.

(d) This test is right-tailed as in the alternative hypothesis we are concerned for proportion of baby girls that is greater than 0.50.

(e) The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of baby girls = $\frac{78}{144}$ = 0.54

n = sample of births = 144

So, the test statistics = $\frac{0.54-0.50}{\sqrt{\frac{0.54(1-0.54)}{144} } }$

= 0.96

The value of z test statistics is 0.96.

(f) The P-value of the test statistics is given by;

P-value = P(Z > 0.96) = 1 - P(Z < 0.96)

= 1 - 0.8315 = 0.1685

(g) Now, at 0.10 significance level the z table gives critical value of 1.282 for right-tailed test.

(h) Since our test statistic is less than the critical value of z as 0.96 < 1.282, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region (which was to the right of value of 1.282) due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of baby girls is equal to 0.50.

7 0

3 years ago

What is this volume?

SSSSS [86.1K]

? Sorry dude I don’t think you added an attachment

3 0

3 years ago

Read 2 more answers

Have you ever been on or seen a ride like this at a fair or amusement park? Imagine being strapped into your seat at the bottom

Marysya12 [62]

The linear relationship is y = 20x, 0 ≤ x ≤ 17.5 and the quadratic relationship is y = -16x² + 288, 0 ≤ x ≤ 3√2

<h3>The equations that represent the relationships</h3>

The linear relationship

When making the trip up, we have:

Rate = 20 feet per seconds

This means that the relationship is:

Distance = Rate * Time

So, we have:

y = 20x

The height of the tower is 350.

So, we have:

20x = 350

Divide by 20

x = 17.5

Hence, the linear relationship is y = 20x, 0 ≤ x ≤ 17.5

The quadratic relationship

The quadratic equation can be represented as:

y = -0.5ax² + vx + h

Where:

a = acceleration due to gravity = 32
v = velocity = 0
h = height = 288

So, we have:

y = -0.5 * 32x² + 0 * x + 288

Evaluate

y = -16x² + 288

When you get to the ground level, we have:

-16x² + 288 = 0

Subtract 288 from both sides

-16x² = -288

Divide by -16

x² = 18

Take the square root of both sides

x = ±3√2

Remove negative domain

x = 3√2

Hence, the quadratic relationship is y = -16x² + 288, 0 ≤ x ≤ 3√2

Read more about linear and quadratic equations at:

brainly.com/question/72196

#SPJ1

5 0

2 years ago

What is the average rate of change from x = −3 to x = −4?

Vika [28.1K]

Answer:

-2

Step-by-step explanation:

Since it would be immensely helpful to know the equation of this parabola, we need to figure it out before we can continue. We have the work form of a positive upwards-opening parabola as

$y=a(x-h)^2+k$

where a is the leading coefficient that determines the steepness of lack thereof of the parabola, x and y are coordinates of a point on the graph, and h and k are the coordinates of the vertex. We know the vertex: V(-3, -3), and it looks like the graph goes through the point P(-2, -1). Now we will fill in the work form equation and solve for a:

$-1=a(-2-(-3))^2-3$

which simplifies a bit to

$-1=a(1)^2-3$

and

-1 = a(1) - 3. Therefore, a = 2 and our parabola is

$y=2(x+3)^2-3$

Now that know the equation, we can find the value of y when x = -3 (which is already given in the vertex) and the value of y when x = -4. Do this by subbing in the values of x one at a time to find y. When x = -3, y = -3 so the coordinate of that point (aka the vertex) is (-3, -3). When x = -4, y = -1 so the coordinate of that point is (-4, -1). The average rate of change between those 2 points is also the slope of the line between those 2 points, so we will use the slope formula to find it:

$m=\frac{-1-(-3)}{-4-(-3)} =\frac{2}{-1}=-2$

And there you have it! I'm very surprised that this question sat unanswered for so very long! I'm sorry I didn't see it earlier!

5 0

3 years ago

Complete this pattern 3400000, 34000,______3.4,______

Complete this pattern 3400000, 34000,3.4,