Answer:

Step-by-step explanation:
Since the fractions are like, their denominators are 11, then
consider the values that sum to give 18 , that is
1 + 9 + ? = 18
10 + ? = 18 ( subtract 10 from both sides )
? = 8
Then the third fraction is 
Answer:
The speed of the bus is 74.242 kilometers per hour.
Step-by-step explanation:
Let suppose that bus runs at constant speed and that speed is measured in kilometers per hour. Then, the speed of the bus (
), in kiometers per hour, is determined by following kinematic expression:
(1)
Where:
- Travelled distance, in kilometers.
- Time, in hours.
If we know that
and
, then the speed of the bus is:


The speed of the bus is 74.242 kilometers per hour.
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is

, and

.
There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.
That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are

and

. The difference of those two cubes is:

In our problem, a = 4 (since

= 64) and b = y (since

. Plug these values into the rule to find the factor of

:

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Answer:
The answer to this question is false because it cannot still be both negative after you reflect over two positives.
Answer:
![1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}](https://tex.z-dn.net/?f=1.%20%5Cquad%5Cdfrac%7B1%7D%7Bk%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%5C%5C%5C%5C2.%20%5Cquad%5Csqrt%5B7%5D%7Bx%5E5%7D%5C%5C%5C%5C3.%20%5Cquad%5Cdfrac%7B1%7D%7B%5Csqrt%5B5%5D%7By%5E2%7D%7D)
Step-by-step explanation:
The applicable rule is ...
![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
It works both ways, going from radicals to frational exponents and vice versa.
The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.