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gregori [183]
4 years ago
11

In this exercise, we estimate the rate at which the total personal income is rising in the Richmond-Petersburg, Virginia, metrop

olitan area. In 1999, the population in this area was 961400, and the population was increasing at roughly 9200 people per year. The average annual income was 30593 dollars per capita, and this average was increasing at about 1400 dollars per year.
Mathematics
1 answer:
Alla [95]4 years ago
7 0

The question is incomplete The complete question is

Estimate the rate at which the total personal income is rising. The population is 961,400 and it increases by 9,200 people per year. The average annual income is 30,593 dollars per capita, and this increases by 1,400 dollars per year.  Using the product rule, estimate the rate at which the total personal income rises.

Answer:

The answer is 3.58%

Step-by-step explanation:

The population of the area = 961,400

Population increase at the rate of 9,200 per year

Average annual income = $30,593

Average annual income increase rate at $1400 per year.

The total annual income will be calculated as population of the area times the average annual income

$961,400 X $30,593 = $29,412,110,200

The expected annual income increase for the entire population will be calculated as average annual income increase times entire population

$1,400 X 961,400 =  $1,345,960,000

 Then the annual income after increase will be a summation of average total annual income and the expected annual increase in income

$29,412,110,200 + $1,345,960,000 =$30,758,070,200

To get the total population after increase, we add the total population to the rate of increase of the population

961,400 + 9,200 =970,600

To get the expected average annual income after increase we divide the total annual income after increase by the total population after increase  

$30,758,070,200 / 970,600 =$31,689.75

Finally, to get the total annual income increase for the entire population, we divide the average annual income increase by the average annual income

$31,689.75/$30,593.00=1.0358 - 1 =.0358 X 100 =3.58%

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Anna35 [415]

Answer:

Therefore the amount in the 4% savings account = $550

Step-by-step explanation:

i) the total amount = $1500

ii) let the amount placed in the 4% interest savings account = x

iii) let the amount placed in the 5% interest savings account  = y

iv) therefore fro i) we can say  x  +  y = 1500

v) the total interest gained = $69.5

vi) therefore we can write 0.04x + 0.05y = 69.50

vii) multiplying equation vi) with 100 we get 4x + 5y = 6950

viii) Multiplying the equation in iv) by 5 we get 5x + 5y = 7500

ix) Subtracting equation in vii) from equation in viii) we get x = $550

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3 0
4 years ago
How do I answer this question
Gnom [1K]
First you have to make it multiplication so you flip 5/2 around and the two “2’s” will cancel each other so it will be 17/5 or 3 2/5
6 0
3 years ago
The following question has two parts. First, answer part A. Then, answer part B.
Dmitriy789 [7]

Answer:

Her estimate is reasonable.She can make 25 completed centerpieces

Step-by-step explanation:

Estimate 20 flowers per centerpiece.  430 flowers divided by 20 flowers per centerpiece.

430 /20 is approximately 21 centerpieces.  Her estimate is reasonable.

430/20  Divide the top and bottom by 10

43/2  is  21*2 = 42   with 1 left over    21  1/2

We know we underestimated when we rounded 17 to 20.  Se we are a little under with 21.5


Exact answer:

430÷17

17 goes into 43  2 times  (17*2 = 34  43-34 =  9 left over)

17 goes into 90 5 time  (17*5 = 85  90-85 = 5 left over)

She can make 25 completed center pieces      

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4 years ago
Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).
Sliva [168]
To compute the distance between the points, we can apply the distance formula as shown below.

d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5
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Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

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Simplifying this, we have

\angle AA = 36.03^{0}
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\angle CC = 17.10^{0} 

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB
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Answer:

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