I tried my best for this I’m pretty for sure I remember doing this in school but I’m not for sure I hope this helped a little bit
1

is the answer you're looking for.
Splitting up the interval of integration into
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length
. The right endpoints of each subinterval follow the sequence

with
. Then the left-endpoint Riemann sum that approximates the definite integral is

and taking the limit as
gives the area exactly. We have

Write it in y= mx+b form. Subtract 5x from both sides to get 4y = -5x + 100. Divide by 4 so the answer would be y= -5/4x + 25.
Answer:
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Step-by-step explanation:
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