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AlladinOne [14]
2 years ago
10

Subtraction (must show work) 1. d - 27 = 45 2. h - 114 = 28

Mathematics
1 answer:
Arturiano [62]2 years ago
7 0

Answer:

Step-by-step explanation:

1.

d - 27 = 45

add 27

d = 72

2.

h - 114 = 28

add 114

h = 142

3.

-4 + x = 15

add 4

x = 19

4.

-39 + g = 72

add 39

g = 111

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one student wrote 18*d=54 for the sentence "The products of 18 and d equals 54". Another student wrote d*18=54 for the same sent
Aloiza [94]

Answer:

Both are right.

Step-by-step explanation:

The two are both right.

Multiplication in algebra obeys the  cummutative law ( a * b = b * a).

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3 years ago
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soldier1979 [14.2K]

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B

Step-by-step explanation:

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3 years ago
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

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Answer:

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Step-by-step explanation:

Follow the workings in the image I sent.

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Least common multiple of 6 and 23
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common muplties is 138

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