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3 years ago

Choose the correct simplification of the expression (2x − 6)(3x2 − 3x − 6).

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

6 0

Answer:

Option A is correct.

Correct simplification of the given expression = $6x^3-24x^2+6x+36$

Step-by-step explanation:

Given the expression: $(2x-6)(3x^2-3x-6)$

The following steps required for the multiplication of polynomials are:

Distribute each terms of the first polynomial to every term of the second polynomial.

Combine like terms

Apply these steps to the given expressions;

$2x(3x^2-3x-6) -6(3x^2-3x-6)$

when you multiply two terms together you must multiply the coefficient (numbers) and add the exponent.

⇒ $6x^3-6x^2-12x -18x^2 +18x +36$

Combine like terms;

$6x^3-24x^2+6x+36$

Therefore, the correct simplification of the given expression is, $6x^3-24x^2+6x+36$

seraphim [82]3 years ago

3 0

If you would like to solve (2x - 6) * (3x^2 - 3x - 6), you can do this using the following steps:

(2x - 6) * (3x^2 - 3x - 6) = 2x * 3x^2 - 2x * 3x - 2x * 6 - 6 * 3x^2 + 6 * 3x + 6 * 6 = 6x^3 - 6x^2 - 12x - 18x^2 + 18x + 36 = 6x^3 - 24x^2 + 6x + 36

The correct result would be 6x^3 - 24x^2 + 6x + 36.

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Whitepunk [10]

Answer:

$x=\frac{5}{4}$

Step-by-step explanation:

$2x+\frac{5}{8}=3x-\frac{5}{8}$

Subtract 5/8 from both sides:-

$2x+\frac{5}{8}-\frac{5}{8}=3x-\frac{5}{8}-\frac{5}{8}$

$2x+\frac{5}{8}-\frac{5}{8}$

Add like terms:-

$\frac{5}{8}-\frac{5}{8}=0$

$=2x$

$3x-\frac{5}{8}-\frac{5}{8}$

Rule:- $\frac{a}{c} \pm \frac{b}{c}=\frac{a \pm b}{c}$

$\frac{-5-5}{8}$

Subtract, $-5-5=-10$

$=\frac{-10}{8}$

Cancel common factor: 2

$=-\frac{5}{4}$

$=3x-\frac{5}{4}$

---------------

$2x=3x-\frac{5}{4}$

Now, subtract 3x from both sides:-

$2x-3x=3x-\frac{5}{4}-3x$

$-x=-\frac{5}{4}$

Divide both sides by -1:-

$\frac{-x}{-1}=\frac{-\frac{5}{4}}{-1}$

$x=\frac{5}{4}$

OAmalOHopeO

4 0

2 years ago

Read 2 more answers

-2(v-2)=-3-2v plz help its home work

Svetach [21]

-2(v-2)=-3-2v doesn't have a solution

3 0

3 years ago

Answer only if you know HELP PART A AND PART B

VARVARA [1.3K]

Answers:

Part A) There is one pair of parallel sides
Part B) (-3, -5/2) and (-1/2, 5/2)

====================================================

Explanation:

Part A

By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.

------------------------

Part B

The midsegment has both endpoints as the midpoints of the non-parallel sides.

The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.

x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3

y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2

The midpoint of segment PS is (-3, -5/2)

Repeat those steps to find the midpoint of QR

x coord = (x1+x2)/2 = (-2+1)/2 = -1/2

y coord = (x1+x2)/2 = (3+2)/2 = 5/2

The midpoint of QR is (-1/2, 5/2)

Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.

7 0

2 years ago

Factor completely 2x^3 + 14x^2 + 6x + 42.

masha68 [24]

Hello,

2x^3+14x^2+6x+42=2x^2(x+7)+6(x+7)
=(x+7)(2x²+6)
=2(x+7)(x²+3) in IR.

or In C 2(x+7)(x-i√3)(x+i√3)

4 0

3 years ago

What is 5 and 3 quarters

liraira [26]

Answer:

In general, 5 and 3 quarters would be 5.75 :)

Remember, there are 4 quarters in $1.00

7 0

3 years ago