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3 years ago

6 and two thirds in a percentage

2 answers:

8 0

We need a denominator in order to put this into a percentage. Unless the denominator is one, in which we can say 666.6666666... percent.

V125BC [204]3 years ago

3 0

666.6667% because there are 6 wholes. and 2/3= 66.6667% 6=600% then add 66.6667%

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During a musical an orchestra is playing. As the music plays, the volume changes in the beginning of the piece can be modeled by

noname [10]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the model:

s = 10│x - 4│+ 50

s represents the sound level in decibels and x represents the number of measures of music played

To find x at s = 80

The equation becomes /

80 = 10│x - 4│+ 50

Subtract 50 from both sides of the equation

80 - 50 = 10 |x - 4| + 50 - 50

30 = 10 | x - 4 |

Divide both sides by 10

30/10 = 10|x - 4| / 10

3 = |x - 4|

|x - 4| is an absolute value expression

±3 = |x - 4|

x = 3 + 4 = 7

x = - 3 + 4 = 1

4 0

3 years ago

Help giving brainly if correct show work to get full points

prohojiy [21]

Answer:

Step-by-step explanation:

This is an geometric series.

Common ratio = second number÷ first number

$= \dfrac{4096}{-1024} = -4$

To get the next number, 256 should be divide by (-4)

$\dfrac{256}{(-4)}= -64 \\\\\\\dfrac{-64}{-4}=16\\\\\\\dfrac{16}{-4}=-4$

The three numbers are : -64 , 16 , -4

6 0

2 years ago

HELPP ASAP!!<br> WHats the area?

Ira Lisetskai [31]

the answer should be 24 because you can divide it into 2 shapes and solve them separately and add those products

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2 years ago

Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:

Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ $14(\frac{4}{5} )$

⇒ $14(0.8 )$

⇒ $11.2$

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ $14(1.25 )$

⇒ $17.5$

Subtracting Maria's - Trenton's :

⇒ $17.5-11.2=6.3$

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

3 0

3 years ago

10 families were asked how many pets they have.here i8s the data.2,3,3,5,4,2,4,0,1,3 find the mean ,medianand mode of the data?

VladimirAG [237]

The mean is 2.7.
The median is: 3
The mode is 3.
Hope this helps!
pls give Brainliest answer!
p.s. if you need an explanation of how to find the mean, median, and mode, just pm me.

4 0

3 years ago

Read 2 more answers