43 not 100% shure good luck
Answer:
ok so 3-1.7=1.3
Step-by-step explanation:
this is bc 3-1=2-0.7=1.3
First, find the z-score:
z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33
In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)
Looking at the table, we find P(z < 0.33) = 0.6293
Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707
Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>
Answer:
Both A and B are true identities
Step-by-step explanation:
A. N ( n − 2 ) ( n + 2 ) = n 3 − 4 n
We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)
So,
n ( n − 2 ) ( n + 2 ) = n(n² - 2²) (difference of two squares)
= n³ - 2²n (expanding the brackets)
= n³ - 4n (simplifying)
So, L.H.S = R.H.S
B. ( x + 1 )² − 2x + y² = x² + y² + 1
We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)
So,
( x + 1 )² − 2x + y² = x² + 2x + 1 - 2x + y² (expanding the brackets)
= x² + 2x - 2x + 1 + y² (collecting like terms)
= x² + 1 + y²
= x² + y² + 1 (re-arranging)
So, L.H.S = R.H.S
So, both A and B are true identities since we have been able to show that L.H.S = R.H.S in both situations.
Answer:
f light is imagined as a flow of particles, the particles are called photons with each photon carrying a discrete packet of energy.
