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2 years ago

Simplify -2.3f + 0.8f - 16 - 3

Mathematics

2 answers:

Gala2k [10]2 years ago

4 0

Answer:

− 1.5 f −19

that's the correct answer.

makkiz [27]2 years ago

3 0

Answer:

Step-by-step explanation:

− 1.5 f − 19

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find the local and/or absolute extrema for the function over the specified domain. (Order your answers from smallest to largest

Arlecino [84]

Answer:

Minimum 8 at x=0, Maximum value: 24 at x=4

Step-by-step explanation:

Retrieving data from the original question:

$f(x)=x^{2}+8\:over\:[-1,4]$

1) Calculating the first derivative

$f'(x)=2x$

2) Now, let's work to find the critical points

Set this

$2x=0\\x=0$

0, belongs to the interval. Plug it in the original function

$f(0)=(0)^2+8\\f(0)=8$

3) Making a table x, f(x) then compare

x| f(x)

-1 | f(-1)=9

0 | f(0)=8 Minimum

4 | f(4)=24 Maximum

4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.

5 0

2 years ago

What is the rate of change of the perimeter of the square at the instant the area is 49 m2?

vagabundo [1.1K]

Let x = the length of a side of the square (m).
The area is
A = x²
The perimeter is
P = 4x

The rate of change of P with respect to x is
P'(x) = 4 (independent of x)

When A = 49 m², then x = 7 m.
The rate of P is 4.

Answer: 4

6 0

3 years ago

WILL MAKE BRAINLIEST!!!!!!!The arc length of a sector is equal to twice the radius. Express the arc length s as a function of th

lilavasa [31]

The area of a circular sector is . 

==> 
Since r = s/2, it follows that , or , or 
.

5 0

3 years ago

An article presents a study of the failure pressures of roof panels. A sample of 15 panels constructed with 8-inch nail spacing

wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

Step-by-step explanation:

From the question we are told that:

Sample size 1 $n_1=15$

Spacing 1 $s_1=8$

Mean 1 $\=x_1=8.48$

Standard deviation 1 $\sigma_1=0.96 kPa$

Sample size 2 $n_2=16$

Spacing 2 $s_2=6$

Mean 1 $\=x_1=9.93$

Standard deviation 1 $\sigma_1=1.02 kPa$

Generally the hypothesis is mathematically given as

Null $H_0:\mu_1-\mu_2$

Alternative $H_a:\mu_1\mu_2$

Generally the equation for pooled estimate is mathematically given by

$S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }$

Therefore

$S=\sqrt{\frac{(15-1)0.96^2+(16-1)1.02^2}{15+15-2} }$

$S=0.9905$

Generally the equation for test statistics is mathematically given by

$t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}$

$t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}$

$t=-4.00091$

Therefore From table

$P value=P(t_{15+15-2}=4.00091)$

$P value=0.00041918$

$P$

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

3 0

2 years ago

Find the slope and the y-intercept of the line. 7x-2y = -10 simplest form

____ [38]

Answer:

7/2 is the slope and 5 is the y-intercept

Step-by-step explanation:

Slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.

7x-2y=-10

subtract 7x on both sides

-2y=-7x-10

divide by -2 on both sides

y=(7/2)x+5

7/2 is the slope and 5 is the y-intercept.

3 0

2 years ago

Read 2 more answers