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sammy [17]
3 years ago
11

Which fraction belongs in the box to make the expression true? 1/4 < ___< 7/8. A. 1/5. B. 8/9. C. 2/10. D. 10/20

Mathematics
2 answers:
Yuri [45]3 years ago
7 0
The answer is D.

In the expression, the fraction must be larger than 1/4, yet smaller than 7/8.

It can't be A because 1/5 is smaller than 1/4. See below.

1/5 = 4/20

1/4 = 5/20

It also can't be B because 8/9 is larger than 7/8. See below.

8/9 = 64/72

7/8 = 63/72

Lastly, the answer cannot be C because 2/10 is smaller than 1/4.

1/4 = 5/20

2/10 = 4/20

Answer D works because:

10/20 = 2/4 > 1/4

10/20 = 80/160 < 140/160



Anastaziya [24]3 years ago
6 0
Here, you need to find a number which is greater than 1/4 and smaller than 7/8.

Now, here we can see 1/5 and 2/10 are equivalent which is smaller than 1/4 [ same numerator and bigger denominator ]

Now, 8/9 is too big among the number, so it is rejected.

The answer would be 10/20 which is equal to 0.5 and lies between them

1/4 < 10/20 < 7/8

In short, Your Answer would be Option D

Hope this helps!
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There are many ways to work this out. One way could be:

Add up:
1/4 + 1/4 + 1/4 = 3/4

Find 3/4 of 8 so;
8 / 4 = 2
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Find what's remaining:
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So Mr.Greg has sandwiches left.
Hope it helped :)
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Step-by-step explanation:

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An automobile firm wants to purchase either machine A or machine B. The intial cost of machines A and B are $40,000 and $50,000,
Fynjy0 [20]

Answer:

C. $118,000 and $110,000, respectively.

Step-by-step explanation:

Please consider the complete question.

An automobile firm wants to purchase either machine A or machine B. The intial cost of machines A and B are $40,000 and $50,000, respectively. The power consumption per year of machines A and B are 120 MWh and 100 MWh, respectively. The power cost is $40/MWh. The estimated operating and maintenance cost over 10 years is $30,000 for machine A and $20,000 for machine B.

First of all, we will find the amount spent on power consumption for 10 years by each machine as:

\text{Machine A}=10\cdot 120(\$40)\\\text{Machine A}=\$48,000

\text{Machine B}=10\cdot \$100(\$40)\\\text{Machine A}=\$40,000

Now, we will find overall cost of machines A and B by adding initial cost, power consumption for 10 years and maintenance cost as:

\text{Overall cost of machine A}=\$40,000+\$48,000+\$30,000

\text{Overall cost of machine A}=\$118,000

\text{Overall cost of machine B}=\$50,000+\$40,000+\$20,000

\text{Overall cost of machine B}=\$110,000

Therefore, the overall cost of machines A and B are $118,000 and $110,000, respectively and option C is the correct choice.

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