We know that:
time=distance/speed
if the tortoise speed is x m/min, then since 0.5 m/hr=1/120 m/min
18/x=23+18/(x+1/120)
solving for x we get:
x=0.08 m/min
speed of hare is:
(0.08+1/120)=0.088 m/min
For each if the differential equation given in Exercises 1 to 12 find the General Solution. xLogx

+y =

Logx...... Hope This Helps
The Minimum sample size table is attached below
Answer:

Step-by-step explanation:
From the question we are told that:
Confidence Interval 
Variance 
Generally going through the table the
Minimum sample size is
