To find the difference, we need to subtract the height of the fish from the height of the bird. If we use sea level as 0, then the bird flies at 1,281 feet, and the fish swims at -282 feet.
1,281 - (-282) = <span>1,281 + 282 = 1,563 feet
There is a </span><span>1,563 feet difference between the height of the bird and the depth of the fish</span>
19/50 when you divide both the numerator and the denominator by 2.
1. The domain of a sqrt(x) is x > 0. So, L > 0.
2. The range of a S(x) = sqrt(x) is S(x) > 0 for all valid x > 0.
Answer: No, you cannot.
Step-by-step explanation: A square number cannot be a perfect number.
The numbers: 0, 1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015, 1240, 1496, 1785, 2109, 2470, 2870, 3311, 3795, 4324, 4900, 5525, 6201 are examples of perfect numbers.
Hello again! So we will be using the pythagorean theorem (

) to solve for the bottom leg of the triangles. After we do that, we'll subtract the value of the legs from 31, and that'll be x.
Plug in 17 and z (or any variable that isn't x) into the leg variable and 19 into the hypotenuse variable, and from there we can solve.

Solve the exponents to get

Subtract 289 on each side to get

Lastly, square root each side of the equation and your answer should be

(To get more accurate answers, you shouldn't round until the end of the problem)
Nextly, we will need to subtract

from 31. And since there are 2 triangles, you'll need to multiply

by 2.
In short, x = 14.0