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Tasya [4]
4 years ago
11

24 +80 distributive property

Mathematics
2 answers:
Dennis_Churaev [7]4 years ago
7 0

Answer:

8(3+10)=104.

Step-by-step explanation:

We are asked to apply the distributive property to solve our given expression 24+80.

First of all, we will find greatest common factor of 16 and 36 as:

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.

Factors of 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.

We can see that the greatest common factor of 24 and 80 is 8.

We can rewrite our given sum as:

8\cdot 3+8\cdot 10

Using distributive property a(b+c)=ab+ac, we will get:

8(3+10)

8(13)

104

Therefore, our expression would be 8(3+10)=104.

Vaselesa [24]4 years ago
3 0

Answer:

140

Step-by-step explanation:

The gcf of 24 and 80 is 8

8(3) + 8(10)    GCF

8(3 + 10)

<u><em>=> 140</em></u>

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Is 6/12 and 15/30 proportional?
sveticcg [70]

Answer:

yes

Step-by-step explanation:

6 is half of 12. 15 is half of 30. The ratios are equal, so the fractions are proportional.

Answer: yes

Also, you can reduce both fractions.

Divide the numerator and denominator of 6/12 by 6 to get 1/2.

Divide the numerator and denominator of 15/30 by 15 to get 1/2.

Since both fractions reduce to 1/2, 6/12 and 15/30 are equivalent fractions and are proportional.

5 0
3 years ago
Find x 10|5x-25|-50=500
diamong [38]

Answer:

x=16

Step-by-step explanation:

10|5x-25|-50=500

+50                     +50

10|5x-25|=550

÷10            ÷10

|5x-25|=55

5x-25=55

+25        +25

5x=80

÷5   ÷5

x=16

8 0
4 years ago
#2) PLEASE HELP WITH QUESTION. MARKING BRAINLIEST + POINTS :}
djverab [1.8K]
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4 years ago
What are the solutions to the quadratic equation x^2-16=0
maks197457 [2]
Good evening.


This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

\mathsf{x^2 - 16 = 0}

Add 16 to both sides:

\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}

Take the square root:

\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}

Therefore:

\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}
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