Answer:
detecting and indicating an electric current
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
- <em>Pressure on the 13 th floor, P₁ = 35 PSI</em>
- <em>Distance between each floor, d = 10 ft</em>
The vertical pressure of the water is calculated as follows;
![P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\](https://tex.z-dn.net/?f=P%20%3D%20%5Crho%20gh%5C%5C%5C%5C%5Cfrac%7BP%7D%7Bh%7D%20%3D%20%5Crho%20g%5C%5C%5C%5C%5Cfrac%7BP%7D%7Bh%7D%20%3D%20k%5C%5C%5C%5C%5Cfrac%7BP_1%7D%7Bh_1%7D%20%3D%20%5Cfrac%7BP_2%7D%7Bh_2%7D%20%5C%5C%5C%5C)
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
![P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI](https://tex.z-dn.net/?f=P_1%20%3D%20%5Cfrac%7BP_2%20h_1%7D%7Bh_2%7D%20%5C%5C%5C%5CP_1%20%3D%20%5Cfrac%7B35%20%5Ctimes%20130%7D%7B10%7D%20%5C%5C%5C%5CP_1%20%3D%20455%20%5C%20PSI)
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
Learn more about vertical height and pressure here: brainly.com/question/15691554
Answer:
Explanation:
a) Energy stored in spring = 1/2 k x² = .5 x k 0.1²
500 = 5 x 10⁻³ k ,
k = (500/5) x 10³ = 10⁵ N/m
b )
k = 4.5 x 10¹ = 45 N/m
Stored energy = 1/2 k x² = .5 x 45 x 8² x 10⁻⁴ =1440 x 10⁻⁴ J
This energy gets dissipated by friction .
work done by friction = μ mg d
d is the distance traveled under friction
so 1440 x 10⁻⁴ = μ x 3 x 9.8 x 2
μ = 245 x 10⁻⁴ or 0.00245 which appears to be very small. .
Answer:a substance with low ability or no ability to conduct energy
Explanation: