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3 years ago

5

Tim adds salt as he starts to heat a pot of water to cook pasta. When the water is boiling, he notices the salt has dissolved ex

plain y

1 answer:

olga nikolaevna [1]3 years ago

4 0

You add salt to increase the boiling point so when its at that point by then all the salt has dissolved because it was warm water

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Projectile Motion—A tennis ball is thrown out a window 28 m above the ground at an initial velocity of 15.0 m/s and 20.0° below

NNADVOKAT [17]

Answer:

The distance will be x = 41.7 [m]

Explanation:

We must first find the components in the x & y axes of the initial velocity.

$(v_{o})_{x} = 15*cos(20)= 14.09[m/s]\\(v_{o})_{y} = 15*sin(20)= 5.13[m/s]$

The acceleration is the gravity acceleration therefore.

g = 9.81 [m/s^2]

Now we can calculate how long it takes to fall.

$y=(v_{o})_{y}*t-0.5*g*t^2\\-28 = 5.13*t-0.5*9.81*t^2\\-28=-4.905*t^2+5.13*t\\4.905*t^2-5.13*t=28\\t = 2.96[s]$

With this time we can find the horizontal distance that runs the projectile.

$x=(v_{o})_{x}*t\\x=14.09*2.96\\x=41.7[m]$

5 0

2 years ago

A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same directionWith the given uncertainties, what is

Anika [276]

Answer:

The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.

Explanation:

For 2 quantities A and B represented as

$A\pm \Delta A$ and $B\pm \Delta B$

The sum is represented as

$Sum=(A+B)\pm (\Delta A+\Delta B)$

For the the values given to us the sum is calculated as

$Sum=(2.9+3.9)\pm (0.1+0.2)$

$Sum=6.8\pm 0.3$

Now the since the uncertainity inthe sum is $\pm 0.3$

The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity

Thus closest distance equals $6.8-0.3=6.5$ meters

3 0

3 years ago

Is sound faster than the speed of light ?

IRISSAK [1]

False..................

6 0

2 years ago

Read 2 more answers

a force is applied to an object at rest with a mass of 100 kg. the same force is applied to an object at rest with a mass of 1 k

Dafna1 [17]

The object with the mass ok 1kg will move more quickly because it is lighter than the 100kg object

3 0

3 years ago

Suppose that the moment of inertia of a skater with arms out and one leg extended is 3.0 kg⋅m2 and for arms and legs in is 0.90

babymother [125]

Answer:

Her angular speed (in rev/s) when her arms and one leg open outward is $1.56\frac{rev}{s}$

Explanation:

Initial moment of inertia when arms and legs in is $I_i=0.90 kg.m^{2}$

Final moment of inertia when her arms and on leg open outward, $I_f=3.0 kg.m^{2}$

Initial angular speed $w_i=5.2\frac{rev}{s}$

Let the final angular speed be $w_f$

Since external torque on her is zero so we can apply conservation of angular momentum

$\therefore L_f=L_i$

=> $I_fw_f=I_iw_i$

=> $w_f=\frac{I_iw_i}{I_f}=\frac{0.9\times5.2 }{3.0}\frac{rev}{s}=1.56\frac{rev}{s}$

Thus her angular speed (in rev/s) when her arms and one leg open outward is $1.56\frac{rev}{s}$

7 0

2 years ago