3 years ago

What does it say about the application of Newtons second law of motion in football

1 answer:

8 0

Answer:

Newton's Second Law of Motion states that a force on an object is equal to the mass of the object multiplied by its acceleration ( F = ma ).

The football then exerts an equal amount of force in the opposite direction on the kicker's foot.

Everything in football that has a mass and acceleration will have a force.

Explanation:

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If a body is moving with a constant velocity then it has ................. acceleration

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Answer:

accelerates

Explanation:

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3 years ago

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A 30 N rightward force is exerted on a 7 kg object. There is a 3 N force of friction acting on the object. What is the Weight of

IgorLugansk [536]

Answer:

W = 68.6 N

Explanation:

Given that,

Force acting on a right side = 30 N

Mass of the object, m = 7 kg

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We need to find the weight of the object.

The weight of an object is given by :

W = mg

Substitute all the values,

W = 7 × 9.8

W = 68.6 N

So, the weight of the object is 68.6 N.

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3 years ago

If root-mean-square voltage of a supply is 240 V, calculate the maximum voltage of

Levart [38]

Answer:

Vp= Vr sq. root 2

= 240 × sq. root 2

=339.4 V

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4 years ago

8. Which explains how a plane mirror works?

lesya692 [45]

Answer:

light rays reflect off an object ,strike the mirror ,and are reflected into your eyes

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3 years ago

A 5.30 m long pole is balanced vertically on its tip. What will be the speed (in meters/second) of the tip of the pole just befo

suter [353]

Answer:

v = 17.66 m/s

Explanation:

As we know that the lower end of the pole is fixed in the ground and it start rotating about that end

so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end

so we have

$mgL = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

so we have

$\omega = \sqrt{\frac{6g}{L}}$

now we have

$\omega = \sqrt{\frac{6(9.81)}{5.30}}$

$\omega = 3.33 rad/s$

now the speed of the other tip of the pole is given as

$v = \omega L$

$v = (3.33)(5.30) = 17.66 m/s$

8 0

4 years ago