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2 years ago

15

600 milimeters by 500 millimeters divided by 25 centimeters

1 answer:

ikadub [295]2 years ago

8 0

As 600 mm and 500 mm convert to 60 cm and 50 cm respectively, our problem here becomes (60 cm)(50 cm) / (25 cm), or 120 cm

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2. Use the distributive property to rewrite the following expression.<br> 3(x+5)

baherus [9]

The answer is 3x+15

You multiply the x and 5 by 3 to get 3x and 15

6 0

3 years ago

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

Write two inequalities to compare 39 and -39

Igoryamba

39 >-39 , |39| = |-39| there you go

4 0

3 years ago

-12 to the power of -2

Novosadov [1.4K]

Answer:

144

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

To simplify an expression means to ensure there are no parentheses and no like

Arlecino [84]

Answer:

True, there you go! hope it helps! Please vote Brainliest!

Step-by-step explanation:

8 0

2 years ago