Answer:
- $8000 at 1%
- $2000 at 10%
Step-by-step explanation:
It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.
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<h3>setup</h3>
Let x represent the amount invested at 10%. Then 10000-x is the amount invested at 1%. The total interest earned is ...
0.10x +0.01(10000 -x) = 280
<h3>solution</h3>
Simplifying gives ...
0.09x +100 = 280
0.09x = 180 . . . . . . . subtract 100
x = 2000 . . . . . . divide by 0.09
10000 -x = 8000 . . . . amount invested at 1%
<h3>1.</h3>
$8000 should be invested in the 1% account
<h3>2.</h3>
$2000 should be invested in the 10% account
To calculate who ran more, you add up the total miles
Pat = 2.75+3+2.5 = 8.25
Toby = 2+2.25+3.5 = 7.75
Now subtract to see who ran more
Pat ran 0.5 miles more than Toby.
Hope this helps
The expression we need to solve is:
To solve this problem, we need to not that we can simplify the fraction 2/10 by dividing both number by 2:
