Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
6 orange. 42 total. 6/42 = 1/7 of the M&Ms are orange.
Y=2x^(1/2)
A=2⌠x^(1/2) dx
A=2[ (2/3)x^(3/2) ]
A=(4/3)[ x^(3/2) ] x=[1,4]
A=(4/3)(8-1)
A=(4/3)7
A=28/3 u^2
A=9 1/3 u^2
Answer:
option 3- 5 square root 2
Step-by-step explanation:
