By using a 0.05 significance level, we can conclude that there is sufficient evidence that most medical malpractice lawsuits are dropped or dismissed.
<h3>How to test the claim for the medical malpractice lawsuits?</h3>
Since we have to compare whether the sample proportion is greater than or lesser than the population proportion, a one-tailed test would be used. Also, we would calculate the sample proportion of medical malpractice lawsuits that are dropped or dismissed as follows:
Sample proportion, p = x/n
Sample proportion, p = 502/775
Sample proportion, p = 0.6477
Mathematically, the null and alternative hypothesis is given by:
H₀: p = 0.5
H₁: p > 0.5
For the test statistic can be calculated by using this mathematical expression:
Where:
- represents the sample mean.
- represents the mean.
- n represents the number of subjects.
Substituting the given parameters into the formula, we have;
z = (0.6477 - 0.5)/√(0.5(1 - 0.5)/775)
z = 0.1477/√(0.25/775)
z = 0.1477/0.01796
z = 8.224.
For the p-value, we have:
p(z>8.224) = 0.0000
Therefore, the p-value (0.000) is less than the significance level α = 0.05. Based on this, we would reject the null hypothesis.
Read more on malpractice lawsuits here: brainly.com/question/13032617
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