You can re-write this quotient this way :

What's inside the square root must be greater than or equal to 0, because the domain of the square root function is defined on R+ (which is [0,+∞))
In other word we must find x so that :

at the end we get
28(x-1) ≥ 0
28x - 28 ≥ 0
28x ≥ 28
x ≥ 1
So the answer is B, x ≥ 1
Answer: -1
Explanation:
-a - (-8) + b
-a + 8 + b (because the - - signs cancel out)
-(2) + 8 + (-7)
-2 + 8 - 7 = -1
To find the answer, you have to set each one equal to each other.
(160 + 40x = 55x)
Now, you just solve for X.
55x - 40x = 15x
160 / 15 = 15 / 15x
This means 160/15 = x, or is equal to
10 2/3