If f(x) is a third degree polynomial function, how many distinct complex roots are possible
2 answers:
2. You will have on real root, and two complex which derives from the 3rd degree polynomial function.
Answer: 2
Step-by-step explanation:
We know that complex roots occurs only in pairs.
If f(x) is a third degree polynomial then by corollary to the fundamental theorem of algebra , it must have 3 roots.
But as complex roots occurs in pairs, thus there must be even number of complex roots.
So there is 2 complex distinct complex roots are possible in third degree polynomial.
Corollary to the fundamental theorem states that every polynomial of degree n>0 has exactly n zeroes.
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-1 is the answer hope I helped
Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
Romashka [77]
The triangles ABC and A'B'C' are shown in the diagram below. The transformation is a reflection in the line
. This is proved by the fact that the distance between each corner ABC to the mirror line equals to the distance between the mirror line to A'B'C'.
Answer:
The possible length is greater than 29 meters.
Step-by-step explanation:
If the length is x then the width is x - 2 m.
So the perimeter is 2x + 2(x - 2) = 4x - 4 m.
4x - 4 > 112
4x > 116
x > 29 m.
Answer:
Its A :))
Step-by-step explanation:
Answer:
16.666% would be flawed.
Step-by-step explanation: