Answer:
Rope jumping, slow pace, < 100 skips/min, 2 foot skip, rhythm bounce 8.8 630
Rope jumping, moderate pace, 100-120 skips/min, general, 2 foot skip, plain bounce 11.8 845
Rope skipping, general 12.3 881
Rope jumping, fast pace, 120-160 skips/min 12.3 881
Step-by-step explanation:
Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
Answer:
The answer is
, by using the <u>Subtraction Property of Equality</u>.
Step-by-step explanation:
Solve for
:

Turn the equation over:

-Subtract both sides by
by using <u>Subtraction Property of Equality</u>:


So, the final answer is
.
Answer:
Step-by-step explanation:
4x5 1/8
= 4 × 41/8
= 41/2
= 20 1/2