If f(x) is a third degree polynomial function, how many distinct complex roots are possible
2 answers:
2.
You will have on real root, and two complex which derives from the 3rd degree polynomial function.
Answer: 2
Step-by-step explanation:
We know that complex roots occurs only in pairs.
If f(x) is a third degree polynomial then by corollary to the fundamental theorem of algebra , it must have 3 roots.
But as complex roots occurs in pairs, thus there must be even number of complex roots.
So there is 2 complex distinct complex roots are possible in third degree polynomial.
- Corollary to the fundamental theorem states that every polynomial of degree n>0 has exactly n zeroes.
You might be interested in
Answer:
A. d + c = 50
4d + 2c = 174
Step-by-step explanation:
Mark me brainliest
Answer:
8.33333333333%
Step-by-step explanation:
50/6
1. f = g(m1 - m2)/d2
2. f d2 = g(m1 - m2)
3. f d2/g + m1 - m2
4. f d2/g + m2 = m1
5. [Answer] m1 = f d2/g + m2
C because 4 1/3= 13/3
Then (13/3)x9= 39
Lastly 39+4= 43
Answer:
7 pizzas
Step-by-step explanation:
You just minus 72 from 9 and once you get to 9 dollars you still have enough to time the delivery guy and you would have 4 dollars left.