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choli [55]
3 years ago
6

If f(x) is a third degree polynomial function, how many distinct complex roots are possible

Mathematics
2 answers:
inessss [21]3 years ago
7 0
2.
You will have on real root, and two complex which derives from the 3rd degree polynomial function.
Flura [38]3 years ago
3 0

Answer: 2


Step-by-step explanation:

We know that complex roots occurs only in pairs.

If f(x) is a third degree polynomial then by corollary to the fundamental theorem of algebra , it must have 3 roots.

But as complex roots occurs in pairs, thus there must be even number of complex roots.

So there is 2 complex distinct complex roots are possible in third degree polynomial.


  • Corollary to the fundamental theorem states that every polynomial of  degree n>0 has exactly n zeroes.

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sertanlavr [38]

Answer:

Yes.

Step-by-step explanation:

You can find it out by factoring but ill do it easier way.

(x + 1 ) = 0 put the first and second equation to 0

x = -1

x³ + 2x² - 5x - 6 = 0  Now plug in the x in the equation

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5 0
3 years ago
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If vector u = &lt;-3.5, -1.5&gt; and vector v = &lt;-1.25, 2.25&gt;, which graph shows the resulting vector for 2v − u?
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Answer:

D

Step-by-step explanation:

We know that vector addition is scalar addition.

Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>

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Answer: We can't even see the whole picture my dude

Step-by-step explanation:

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