Answer: 34.9 cm
Explanation:
You are given the following parameters;
Object distance U = 32 cm
Magnification M = - 12.0
According to formula for magnification;
M = V/U
Where V = image distance.
Substitute V and M into the formula
-12 = V/32
Cross multiply
V = -12 × 32
V = - 384
You can use the formula
1/f = 1/V + 1/U
Where f = focal length
Substitute V and U into the formula
1/f = - 1/384 + 1/32
Find the lowest common factor of the denominator at Left hand side
1/f = ( -1 + 12 ) / 384
1/f = 11/384
Reciprocate both sides
F = 384/11
F = 34.9 cm
He should therefore use the focal length of 34.9 cm
Answer: the answer is 35.4
Explanation: the formula is mass x acceleration = tension - weight
weight is (3kg x 9.8 m/s)
acceleration is 2 m/s
mass = 3kg
It would be A since the axe head acts as a wedge and the handle is a basic lever
Answer:
Heat energy does not cool. Objects cool. Energy is not an object. Now, what happens when an object cools is that it gives off some of its thermal energy by one or more mechanisms: radiation, conduction, or convection. In radiation the energy escaped the object as electromagnetic waves - you see the red hot poker slowly dim as it cools, in conduction the energy is transferred Mechanically by the atoms of the hot object being in physical contact with those of the cool object and in convection the hot material moves to a cooler region where it gives up its heat energy by either radiation or conduction.
Answer
given.
Mass of big fish = 15 Kg
speed of big fish = 1.10 m/s
mass of the small fish = 4.50 Kg
speed of the fish after eating small fish =?
a) using conservation of momentum
m₁v₁ + m₂v₂ = (m₁+m₂) V
15 x 1.10 + 4.50 x 0 = (15 + 4.5)V
16.5 = 19.5 V
V = 0.846 m/s
b) Kinetic energy before collision
![KE_1 = \dfrac{1}{2}m_1v_1^2 + \dfrac{1}{2}m_2v_2^2](https://tex.z-dn.net/?f=KE_1%20%3D%20%5Cdfrac%7B1%7D%7B2%7Dm_1v_1%5E2%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dm_2v_2%5E2)
![KE_1 = \dfrac{1}{2}\times 15 \times 1.1^2 + \dfrac{1}{2}m_2\times 0^2](https://tex.z-dn.net/?f=KE_1%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%2015%20%5Ctimes%201.1%5E2%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dm_2%5Ctimes%200%5E2)
KE₁ = 9.075 J
Kinetic energy after collision
![KE_2= \dfrac{1}{2}(15+4.5)\times 0.846^2](https://tex.z-dn.net/?f=KE_2%3D%20%5Cdfrac%7B1%7D%7B2%7D%2815%2B4.5%29%5Ctimes%200.846%5E2%20)
KE₂ = 6.98 J
Change in KE = 6.98 - 9.075 = -2.096 J
hence,
mechanical energy was dissipated during this meal = -2.096 J