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oksano4ka [1.4K]
4 years ago
5

If you were trying to build a soundproof room, which of the following materials would you choose in order to absorb the most sou

nd, based on the coefficient of absorption for each material?
A. Heavy curtains
B. Wood
C. Concrete
D. Carpet
Physics
2 answers:
leonid [27]4 years ago
5 0

Explanation :  

Absorption coefficient of a material determines how much sound is absorbed by the material.

To build a soundproof room, Heavy curtains and carpet can be used. They reduce reverberation.

Reverberation means an echoing sound which persists for some time. For example, when we bang on a huge piece of metal, we hear the reverberation even after we stop banging.  

Hence, option (A) and (D) are correct.

Margarita [4]4 years ago
5 0
Carpet and heavy curtains, and wood. concrete is more liable to echo. with the heavy carpet, its thick enough to weaken the sounds, as well as carpet. wood is thick and big enough to do the same aswell. hope this helps.
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Create a Graph : Include numbers, axes, and order pairs
dlinn [17]
Answer:

a) Peak value = 20

b) Average value = 9.0

c) RMS value = 14.15

Explanation:

The peak-to-peak value = 40

v_{p-p}=40\begin{gathered} v_{p-p}=2v_p \\  \\ 40=2v_p \\  \\ v_p=\frac{40}{2} \\  \\ v_p=20 \end{gathered}

c) The rms value

\begin{gathered} v_{rms}=\frac{v_p}{\sqrt{2}} \\  \\ v_{rms}=\frac{20}{\sqrt{2}} \\  \\ v_{rms}=14.14 \end{gathered}

b) Average value over alternation of the sine wave

\begin{gathered} v_{avg}=0.637v_p \\  \\ v_{avg}=0.637\times14.14 \\  \\ v_{avg}=9.0 \end{gathered}

6 0
1 year ago
The total energy of a 0.050 kg object travelling at 0.70 c is:
finlep [7]
What is the unit c denotes here
3 0
3 years ago
Read 2 more answers
A rock, with a density of 3.55 g/cm^3 and a volume of 470 cm^3, is thrown in a lake. a) What is the weight of the rock out of th
SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

   Volume = 470 cm³

   Density = 3.55 g/cm³

   Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

   Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

   Volume = 470 cm³

   Density of liquid = 1 g/cm³

   \texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N

c) Mass of the water displaced = Volume of body x Density of liquid

   Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

   Weight of rock under water = 16.37 - 4.61  =11.76 N

3 0
3 years ago
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frozen [14]
F = ma
6.25 N = 0.4 kg · a
a = (6.25/0.4) m/s²      since N=kg·m/s²
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8 0
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Answer:

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