Answer:
These are the two statements with scientific facts that explain the described phenomenon
<span>
Gravitation between two objects increases when the distance between them decreases.</span>
When the mass of an object increases, its gravitational pull also increases.
Justification:
Those two facts are represented in the Universal Law of Gravity discovered by the scientific Sir Isaac Newton (1642 to 1727) and published in his book <span>Philosophiae naturalis principia mathematica.</span>
That law is represented by the equation:
F = G × m₁ × m₂ / d²
The product of the two masses on the numerator accounts for the fact that the gravitational force is directly proportional to the product of the masses, which is that as the masses increase the attraction also increase.
The term d² (square of the distance that separates the objects) in the denominator accounts for the fact that the gravitational force is inversely proportional to the square of the distance; that is as the separation of the objects increase the gravitational force decrease.
Answer:
The acceleration that earth experiences due to gravitational pull is = 9.81 
.
Explanation:
The acceleration that earth experiences due to gravitational pull is called the acceleration due to gravity. its value is 9.81 and its unit is .
When the object move upwards than in that case the earth gravitational force pulls down the body.
The formula of force due to gravity on the body is given as
F = mg
where g = acceleration due to gravity.
Due to this acceleration the body falls upon the surface of the earth.
Answer & Explanation:
1 N-m = 1 Joule
So 82 kJ of energy put into the system during (i).
45 kJ of heat leaves the system, so 82 kJ - 45 kJ = 37 kJ is remaining.
(ii) requires 100 kJ of energy but only 37 kJ is available, so 100 kJ - 37 kJ = 63 kJ of heat energy must be added to the system.
Answer: 630 V
Explanation: In order to solve this problem we have to consider the potential given by:
In the region 0<a<b
V(r)= -∫E*dr where E can be calculated by Gaussian law then E= k*qa/r^2
where qa=-3 nC
then
The V(r)=k*qa/r+C C is zero since V(r=∞)=0
Finally we have
V(r)= k*qa (1/r)-(1/b)
thus V(a)= k*qa (1/a)-(1/b)
Replacing the values V(a) = 630 V, as the solid metal sphere is a equipotential object thus at the center have the same value of V that in r=a ( 630 V).
