I think the answer may be D- mechanical
Every chemical "compound" is. Some examples of compounds include ...
Salt
Carbon dioxide
Alcohol
Water
DNA
Given:
The magnitude of each charge is q1 = q2 = 1 C
The distance between them is r = 1 m
To find the force when distance is doubled.
Explanation:
The new distance is
![\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%5E%7B%5Cprime%7D%3D%5Ctext%7B%202r%7D%20%5C%5C%20%3D2%5Ctimes1%20%5C%5C%20%3D2%5Ctext%7B%20%7Dm%20%5Cend%7Bgathered%7D)
The force can be calculated by the formula
![F=k\frac{q1q2}{(r^{\prime})^2}](https://tex.z-dn.net/?f=F%3Dk%5Cfrac%7Bq1q2%7D%7B%28r%5E%7B%5Cprime%7D%29%5E2%7D)
Here, k is the constant whose value is
![k=9\times10^9\text{ N m}^2\text{ /C}^2](https://tex.z-dn.net/?f=k%3D9%5Ctimes10%5E9%5Ctext%7B%20N%20m%7D%5E2%5Ctext%7B%20%2FC%7D%5E2)
On substituting the values, the force will be
![\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20F%3D9%5Ctimes10%5E9%5Ctimes%5Cfrac%7B1%5Ctimes1%7D%7B%282%29%5E2%7D%20%5C%5C%20%3D2.25%5Ctimes10%5E9%5Ctext%7B%20N%7D%20%5Cend%7Bgathered%7D)