Answer:
The current is 2.0 A.
(A) is correct option.
Explanation:
Given that,
Length = 150 m
Radius = 0.15 mm
Current density
We need to calculate the current
Using formula of current density


Where, J = current density
A = area
I = current
Put the value into the formula


Hence, The current is 2.0 A.
Answer:
Jethro Wood is the one who designed the one-piece wrought iron plow.
The answer to this question lies in the definition of density. One material will just float over another if its density is smaller. If one material is denser than the other, it will sink.
Density can be defined as the mass per unit volume of a substance at a given pressure and temperature.
Thus, for a material to float in water, it does not depend on the weight, or rather on the mass, but on the distribution of the mass by the volume occupied, that is, of the density. The more distributed the mass, that is, the larger its volume, the less dense the object and it will float.
Object C has the lowest density<span>
65 N or 6.5 Kg ------------ 6 N or 6 Kg
This effective mass under water will be its actual mass minus the mass of the fluid displaced.
The buoyant force on a submerged object is equal to the weight of the fluid displaced.
Weight of object - buoyant force on object (the mass of the fluid displaced)
6Kg - 6.5Kg= - 0.5Kg
</span>Answer: C. object C
Candle burning because it’s going from a solid to a liquid
Plz give me a good mark
Answer:
The minimum coefficient of friction is 0.22
Explanation:
Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.
We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.
Given that,
Radius = 85 m
Angle = 15°
Speed = 20 km/h
We need to calculate the ideal speed
Using formula of speed


Put the value into the formula


We need to calculate the minimum coefficient of friction
Using formula for coefficient of friction

Put the value into the formula





Hence, The minimum coefficient of friction is 0.22