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geniusboy [140]
3 years ago
12

Simplify the fractionshow the work

Mathematics
2 answers:
neonofarm [45]3 years ago
7 0
First find a common denominator (The bottom part)

24

now times that to the top part

8 × 3 = 24 so 7 × 3 = 21
3 × 8 = 24 so 10 × 8 = 80
14 × 2 = 24 so 5 × 2 = 10

21/24 × 80/24 × 10/24 = 16,800/24

simplify

400/ 7 or 57 1/7
Oksanka [162]3 years ago
3 0

\frac{7}{8}  \times  \frac{10}{3}  \times  \frac{5}{14}
\frac{7}{8} (\frac{10}{3})(\frac{5}{14})
\frac{35}{12} ( \frac{5}{14}) =  \frac{25}{24}
ANSWER
\frac{25}{24}

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Given $dc = 7$, $cb = 8$, $ab = \frac{1}{4}ad$, and $ed = \frac{4}{5}ad$, find $fc$. Express your answer as a decimal.
Pachacha [2.7K]

A ↔ B ↔ C ↔ D ↔ E ↔ F

 \frac{1}{4} AD      8      7      \frac{4}{5} AD   ???

AB + BC + CD = AD   <em>segment addition postulate</em>

\frac{1}{4} AD   +   8   +   7   = AD

\frac{1}{4} AD   +       15        = AD

AD         + 60    = 4AD

                  60    = 3AD

                  20    = AD

AB =  \frac{1}{4} AD    =  \frac{1}{4}(20)    = 5

DE =  \frac{4}{5}AD   =  \frac{4}{5}(5)    = 4

CD + DE + EF = CF   <em>segment addition postulate</em>

7   +   4   + EF  = CF

     11        + EF  = CF

Answer: 11 + EF

Note: You did not provide any info about EF.  If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.

7 0
3 years ago
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Step-by-step explanation:

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Does the equation I = 3 represent a function? Choose one option from each drop-down menu to explain your answer. For an equation
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Step-by-step explanation:

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We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

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