Answer:
We start with the equation:
A: 3*(x + 2) = 18
And we want to construct equation B:
B: X + 2 = 18
where I suppose that X is different than x.
Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:
3*(x + 2) = X + 2
Now we can isolate the variable x.
(x + 2) = (X + 2)/3
x = (X + 2)/3 - 2
Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.
Let's do it:
A: 3*(x + 2) = 18
Now we can replace x by = (X + 2)/3 - 2
3*( (X + 2)/3 - 2 + 2) = 18
3*( (X + 2)/3 ) = 18
3*(X + 2)/3 = 18
(X + 2) = 18
Which is equation B.
Answer:
x=45
Step-by-step explanation:
2/5x-10=8
2/5x=18
x=18÷2/5
x=18(5/2)
x=45
Begin
3x-4=14
3x=18
x=6
.5n=1.25
n=2.5
x+1=2x-2
x+3=2x
3=x
x+3=10
x=7
6x-13=-11
6x=2
x=1/3
p=4-p
2p=4
p=2
End
Not really sure whats up with that inequality but she can't, if she has to spend 1.5 hours in a lab that leaves her with 5 hours. 5/4 is 1.25, so no, she can only spend 1.25 hours with each student.
8 x/3 apply the formula x power/root. Hope that helped!
