The result of the respective questions are:
- This chi-square test only takes into consideration one variable.
- The type of chi-square test this is is a Goodness of Fit
- df= 3
- NO
<h3>How many variables are involved in the chi-square test?</h3>
a)
This chi-square test only takes into consideration one variable.
b)
The type of chi-square test this is, is a Goodness of Fit
To test the hypothesis, we must determine whether the actual data conform to the assumed distribution.
The "Goodness-of-Fit" test is a statistical hypothesis test that determines how well the data that was seen resembles the data that was predicted.
c)
Parameter
n = 4
Therefore
Degrees of freedom
df= n - 1
df= 4 - 1
df= 3
d)
In conclusion
Parameters
df = 3
Hence
Critical value = 7.814728
Test statistic = 6.6
Test statistic < Critical value, .
NO, the result of this test is not statistically significant.
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Answer:
Option D
Step-by-step explanation:
If the whole grid is considered to be 1,
Each small grid will value = 
There are 72 shaded grids which represent the hundreds = 0.72
When these grids have been divided into 9 equal rows, number of grids in each row = 8
And the value of 8 grids in each row = 0.01 × 8 = 0.08
So the equation is,
0.72 ÷ 9 = 0.08
Therefore, equation represented by the model will be Option (D).
2x + y = 1
2x - 2x + y = 1 - 2x
y = 1 - 2x
y = -2x + 1
4x + 2y = -1
4x + 2(-2x + 1) = -1
4x + 2(-2x) + 2(1) = -1
4x - 4x + 2 = -1
2 ≠ -1
The solution of the problem can't be a solution because they are both parallel lines, which means they have no solution.
Answer:
D. 18.9 ÷ 9
Step-by-step explanation:
we need to divide
1.89 ÷ 0.9 but write it in different form
so ,we need to eliminate decimal from 0.9
as 0.9*10 = 9
thus,we multiply both 1.89 and 0.9 with 10, then we will have
(1.89*10) ÷ (0.9*10)
=> 18.9 ÷ 9
Thus, based on above calculation new look would be D. 18.9 ÷ 9
