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Helga [31]
3 years ago
5

Find all the real zeros of f(x)=3x^3-9x^2+3x-9 Can someone help me please

Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

x=0,3

Step-by-step explanation:

start by dividing every term by 3

x^3-3x^2+x-3

group into 2 terms

(x^3-3x^2)+(x-3)

simplify as much as you can

x^2(x-3)+(x-3)

combine terms

(x^2)(x-3)

x=3, 0

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I’m Not 100% Sure, But I Would Think 13.1% Is The Answer.
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A convex parabola is shown in a coordinate plane. The parabola connects the points left-parenthesis negative 4.5 comma 12 right-
spayn [35]

Since the parabola is connecting the points, it means that the points given are on the parabola or that the points are solutions of the parabola. Thus, when we substitute the points into the function, we should end up with the correct y-value.


To find the correct choice, let's test a point. An easy point to test I believe would be (-3, 0) because we should be getting 0 as a y-value. Let's test:

A. (- 3 - 3)(3 + 4) = -42

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We can see that Choice B is the correct function, because it produces 0 when we substitute x = - 3. Thus, Choice B, or (x + 3)(x - 4) is the answer.

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3 years ago
True or false: you flip the sign every time you multiply or divide when you're solving an
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2 years ago
Collin is building a deck on the back of his house. He has enough lumber for the deck to be 144 square feet. The length should b
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Width = x
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Solving for x in a quadratic:

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4 0
3 years ago
List the angles in triangle QRS from smallest to largest.
schepotkina [342]

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angle R

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suppose,

q = 6.25

s = 11.04

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angleQ = cos^{-1}(\frac{13.19^{2}+11.04^{2}-6.52^{2}}{2(13.19)(11.04)})

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angleR = cos^{-1}(\frac{6.52^{2}+11.04^{2}-13.19^{2}}{2(6.52)(11.04)})

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angleS =  cos^{-1}(\frac{6.52^{2}+13.19^{2}-11.04^{2}}{2(6.52)(13.19)})

            = 56.63

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3 years ago
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