Find all the real zeros of
f(x)=3x^3-9x^2+3x-9
Can someone help me please
1 answer:
Answer:
x=0,3
Step-by-step explanation:
start by dividing every term by 3
x^3-3x^2+x-3
group into 2 terms
(x^3-3x^2)+(x-3)
simplify as much as you can
x^2(x-3)+(x-3)
combine terms
(x^2)(x-3)
x=3, 0
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