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3 years ago

Find all the real zeros of f(x)=3x^3-9x^2+3x-9 Can someone help me please

Mathematics

1 answer:

vaieri [72.5K]3 years ago

4 0

Answer:

x=0,3

Step-by-step explanation:

start by dividing every term by 3

x^3-3x^2+x-3

group into 2 terms

(x^3-3x^2)+(x-3)

simplify as much as you can

x^2(x-3)+(x-3)

combine terms

(x^2)(x-3)

x=3, 0

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3 years ago

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3 years ago

A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of

hram777 [196]

$\sf\huge\underline{\star Solution:-}$

$\rightarrow$ <u>Ratio of two angles are 6:13.</u>

So, let the one angle be $\sf{6x}$ and another be $\sf{13x.}$

As we know that,

Sum of all interior angles of a quadrilateral = $\sf\pink{360°.}$

So let's sum up the given angles,

$\rightarrow$ $\sf{222°+81°+6x+13x \:=\: 360°}$

$\rightarrow$ $\sf{303+19x \:=\: 360°}$

$\rightarrow$ $\sf{19x \:=\: 360-303}$

$\rightarrow$ $\sf{19x \:=\: 57}$

$\rightarrow$ $\sf{x \:=\: \frac{19}{57}}$

$\rightarrow$ $\sf{x \:=\: 3}$

Hence, $\sf{x \:=\: 3}$

So, First angle $\sf{= \:6x\: = \:6×3 \:=}$ $\sf\purple{18°.}$

Second angle $\sf{= \:13x\: = \:13×3 \:=}$ $\sf\purple{39°.}$

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Hope it helps you:)

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2 years ago

Suppose you have a right triangle with side lengths 26, 24, and 10. Which lengths

solong [7]

Answer:

hypotenuse —>26

Legs —> 10 and 24

Step-by-step explanation:

Generally ,the hypotenuse is the longest side .

So in our triangle the hypotenuse is of length 26.

Consequently, the legs are of lengths 24 and 10.

Also ,we can verify that this is right triangle using the Pythagorean theorem:

26^2 = 676

24^2+10^2 = 676

Then

26² = 24²+10².

3 0

2 years ago