Answer:
The first car is traveling at a speed of
s1=62 mi/hr.
The second car is traveling at a speed of s2=67 mi/hr.
Step-by-step explanation:
Let t be the amount of time the cars are traveling
s1=248/t and s2=268/t
We are told:
s1=s2-5
That is
248/t=268/t-5
⇒248=268- 5t
⇒5t=20
⇒t=4
s1=248/4=62
s2=268/4=67
Step-by-step explanation:
you can simply multiply things out.
4/9 × y = 8/3
4y = 9×8/3 = 3×8 = 24
y = 6
or you could have transformed the right hand side into a fraction of the same denominator (9) :
8/3 = 8/3 × 3/3 = (8×3)/(3×3) = 24/9
4/9 × y = 24/9
that means 4y = 24
y = 6
Answer:
j = -8
Step-by-step explanation:
-13j - 20 = -8j + 20
Add 13 j to each side
-13j+13j - 20 = -8j+13j + 20
-20 = 5j+20
subtract 20 from each side
-20-20 = 5j +20-20
-40 = 5j
Divide by 5
-40/5 = =5j/5
-8 =j
