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2 years ago

2(2x+3)=3(3x+1) Duýdhdhdjjdjdjđm

Mathematics

2 answers:

Vlada [557]2 years ago

7 0

Answer:

Step-by-step explanation:

.......................

Dima020 [189]2 years ago

5 0

Answer:

x=1/2

Step-by-step explanation:

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The area of a rectangle is 6x^2-9x-15. And the length is (2x-5). Which expression best represents the rectangle’s width?

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<h2>AnswEr : </h2>

The area of the rectangle is of the form 6x² - 9x - 15

Factoring the given expression,

$\sf \: {6x}^{2} - 9x - 15 \\ \\ \leadsto \: \sf \: 3\bigg( {2x}^{2} - 3x - 5 \bigg) \\ \\ \leadsto \: \sf \: 3 \bigg( {2x}^{2} - 5x + 2x - 5 \bigg) \\ \\ \leadsto \: \sf \: 3 \bigg((2x - 5)(x + 1) \bigg)$

Length of the rectangle is 2x - 5

Thus,

$\leadsto \: \sf \: (2x - 5)(3x + 3)$

<h3>The breadth of the rectangle is 3x + 3 </h3>

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation: 7829219882 / 278892828891271289289

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3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

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3 years ago