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3 years ago

What is 10x9= what is the answer to my questions slows

Mathematics

2 answers:

vredina [299]3 years ago

8 0

90 is the answer it’s the answer

Aleks [24]3 years ago

7 0

Answer:

90.

Step-by-step explanation:

10, 9 times, means you're adding 10+10+10+10+10+10+10+10+10=90.

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A stereo costs $418.70, including 6% sales tax. How much was the sales tax itself?

gulaghasi [49]

Answer:

25.12

Step-by-step explanation:

3 0

3 years ago

HELP ME ASAP PLEASE!!

lilavasa [31]

Answer:

a=45 b=65

Step-by-step explanation:

You know that all the angle measures of a triangle add to 180. So the equation would be angle a + angle b + 70 = 180. Subsitute and simplify and you get 16x -2 + 70 = 180. Subtract 70 from 180 to get 16x -2=110 add 2 to get 16x =110. Divide each side by 16 to gte x=7. Subsitute x = 7 into the equations for angle a and angle b to get the answers above

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2 years ago

Grandma put 1⁄6 teaspoon of pepper into the soup. After tasting the soup, she added 1⁄8 teaspoon of pepper. How much pepper is i

alexandr1967 [171]

Add 1/6 teaspoon and 1/8 teaspoon. The LCD here is 24, so we're adding
4/24 to 3/24, obtaining 7/24 (teaspoon of pepper, total).

3 0

3 years ago

Juan fode his bike 2/3 mile to school,1/3 mile to the library,2/3 mile home far did he ride altogether

Viktor [21]

Answer:1 2/3

Step-by-step explanation:

2/3+1/3+2/3=5/3=1 2/3

7 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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3 0

1 year ago