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Komok [63]
3 years ago
5

Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2 x .

Mathematics
2 answers:
Svetach [21]3 years ago
7 0
The correct functions are
<span>h(x) = 3x + 2  
g(x) = 2</span>^<span>x

</span>I proceed to calculate the different values ​​of K (x)<span>
case 1) </span><span>k(x) = g(x) ∘ h(x)
</span>g(x) ∘ h(x)=g(h(x))
k(x) = [2]^[3x + 2]-----------> is the option 4. k(x) = 2^(3x + 2 )
<span> 
case 2) </span><span>k(x) = g(x) + h(x)
</span>k(x) = [2^x]+[3x + 2]=2^x+3x+2--------> is the option 1.) k(x) = 2^<span>x + 3x + 2

case 3)</span><span>k(x) = h(x) ÷ g(x)
</span>k(x) = [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)
is the option 3.)  k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)<span>k(x) = g(x) - h(x)
</span>k(x) = [2^x]-[3x + 2]=2^x-3x-2--------> is the option 2.) k(x) = 2^<span>x - 3x - 2 

case 5) </span>k(x) = g(x) × h(x)
k(x) = [2^x]*[3x + 2]-----------> is the option 5.) k(x) = 2^x(3x + 2)

case 6)<span>k(x) = h(x) ∘ g(x)
</span>h(x) ∘ g(x)=h(g(x))
k(x)=3*[2^x]+2---------------> is the option 6. k(x) = 3(2^x) + 2 
Aleksandr-060686 [28]3 years ago
6 0

To simplify the other user's answer (which is correct):

1 = B

2 = D

3 = C

4 = A

5 = E

6 = F

Alternatively, your right boxes should look like:

4

1

3

2

5

6

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Add a comment

3 Answers

1

Consider the following Argand-diagram

enter image description here

The y-axis is the imaginary axis and the x-axis is the real one. The complex number in question is

x+yi

To figure out θ, consider the right-triangle formed by the two-coordinates on the plane (illustrated in red). Let θ be the angle formed with the real axis.

tanθ=yx

⟹tan−1(yx)

The hypotenuse of the triangle will be

x2+y2−−−−−−√

Therefore,

Step-by-step explanation:

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3 years ago
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diamong [38]

Answer:

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Step-by-step explanation:

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