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Komok [63]
3 years ago
5

Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2 x .

Mathematics
2 answers:
Svetach [21]3 years ago
7 0
The correct functions are
<span>h(x) = 3x + 2  
g(x) = 2</span>^<span>x

</span>I proceed to calculate the different values ​​of K (x)<span>
case 1) </span><span>k(x) = g(x) ∘ h(x)
</span>g(x) ∘ h(x)=g(h(x))
k(x) = [2]^[3x + 2]-----------> is the option 4. k(x) = 2^(3x + 2 )
<span> 
case 2) </span><span>k(x) = g(x) + h(x)
</span>k(x) = [2^x]+[3x + 2]=2^x+3x+2--------> is the option 1.) k(x) = 2^<span>x + 3x + 2

case 3)</span><span>k(x) = h(x) ÷ g(x)
</span>k(x) = [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)
is the option 3.)  k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)<span>k(x) = g(x) - h(x)
</span>k(x) = [2^x]-[3x + 2]=2^x-3x-2--------> is the option 2.) k(x) = 2^<span>x - 3x - 2 

case 5) </span>k(x) = g(x) × h(x)
k(x) = [2^x]*[3x + 2]-----------> is the option 5.) k(x) = 2^x(3x + 2)

case 6)<span>k(x) = h(x) ∘ g(x)
</span>h(x) ∘ g(x)=h(g(x))
k(x)=3*[2^x]+2---------------> is the option 6. k(x) = 3(2^x) + 2 
Aleksandr-060686 [28]3 years ago
6 0

To simplify the other user's answer (which is correct):

1 = B

2 = D

3 = C

4 = A

5 = E

6 = F

Alternatively, your right boxes should look like:

4

1

3

2

5

6

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Answer:

Equation:   x + (x+ 1) = 67

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We want to find two consecutive integers.

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<h3>Answer:</h3>
  1. C. (9x -1)(x +4) = 9x² +35x -4
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Step-by-step explanation:

1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.

2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...

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... d = 480 . . . . . . . . divide by 2

The second voyage lasted 480 days.

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mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
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