Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2 x .
2 answers:
The correct functions are
<span>h(x) = 3x + 2
g(x) = 2</span>^<span>x
</span>I proceed to calculate the different values of K (x)<span>
case 1) </span><span>k(x) = g(x) ∘ h(x)
</span>g(x) ∘ h(x)=g(h(x))
k(x) = [2]^[3x + 2]-----------> is the option 4. k(x) = 2^(3x + 2 )
<span>
case 2) </span><span>k(x) = g(x) + h(x)
</span>k(x) = [2^x]+[3x + 2]=2^x+3x+2--------> is the option 1.) k(x) = 2^<span>x + 3x + 2
case 3)</span><span>k(x) = h(x) ÷ g(x)
</span>k(x) = [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)
is the option 3.) k(x) = (3x)2^(-x) + 2^(-x + 1 )
case 4)<span>k(x) = g(x) - h(x)
</span>k(x) = [2^x]-[3x + 2]=2^x-3x-2--------> is the option 2.) k(x) = 2^<span>x - 3x - 2
case 5) </span>k(x) = g(x) × h(x)
k(x) = [2^x]*[3x + 2]-----------> is the option 5.) k(x) = 2^x(3x + 2)
case 6)<span>k(x) = h(x) ∘ g(x)
</span>h(x) ∘ g(x)=h(g(x))
k(x)=3*[2^x]+2---------------> is the option 6. k(x) = 3(2^x) + 2
To simplify the other user's answer (which is correct):
1 = B
2 = D
3 = C
4 = A
5 = E
6 = F
Alternatively, your right boxes should look like:
4
1
3
2
5
6
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I would say 18 because if they are similar they would need to have the same starting point so if the first was multiplied than so should the second.
It's C.
2/5 x 3 = 1 1/5 = 6/5
Happy to Help!
Answer:
x = 20
Step-by-step explanation:
3x = 40 + x
-x -x
2x = 40
Divide both sides by 2
x = 40/2
x = 20
I hope this was helpful! <3
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