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Komok [63]
3 years ago
5

Match the corresponding function formula with each function when h(x) = 3x + 2 and g(x) = 2 x .

Mathematics
2 answers:
Svetach [21]3 years ago
7 0
The correct functions are
<span>h(x) = 3x + 2  
g(x) = 2</span>^<span>x

</span>I proceed to calculate the different values ​​of K (x)<span>
case 1) </span><span>k(x) = g(x) ∘ h(x)
</span>g(x) ∘ h(x)=g(h(x))
k(x) = [2]^[3x + 2]-----------> is the option 4. k(x) = 2^(3x + 2 )
<span> 
case 2) </span><span>k(x) = g(x) + h(x)
</span>k(x) = [2^x]+[3x + 2]=2^x+3x+2--------> is the option 1.) k(x) = 2^<span>x + 3x + 2

case 3)</span><span>k(x) = h(x) ÷ g(x)
</span>k(x) = [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)
is the option 3.)  k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)<span>k(x) = g(x) - h(x)
</span>k(x) = [2^x]-[3x + 2]=2^x-3x-2--------> is the option 2.) k(x) = 2^<span>x - 3x - 2 

case 5) </span>k(x) = g(x) × h(x)
k(x) = [2^x]*[3x + 2]-----------> is the option 5.) k(x) = 2^x(3x + 2)

case 6)<span>k(x) = h(x) ∘ g(x)
</span>h(x) ∘ g(x)=h(g(x))
k(x)=3*[2^x]+2---------------> is the option 6. k(x) = 3(2^x) + 2 
Aleksandr-060686 [28]3 years ago
6 0

To simplify the other user's answer (which is correct):

1 = B

2 = D

3 = C

4 = A

5 = E

6 = F

Alternatively, your right boxes should look like:

4

1

3

2

5

6

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Identify whether the following equation has a unique solution, no solution, or infinitely many solutions.
fredd [130]

Answer:

no solution

Step-by-step explanation:

4( − 11) = 15 − 4

-44 = 11

Since this iS FALSE, it means that the equation given has no solution

7 0
3 years ago
Can someone please help me I don't understans
Lemur [1.5K]
The question is asking which formula will give the results
1, 9, 36, 100, 225, ...
for k values of
1, 2, 3, 4, 5, ...

You can try them out to see.
A) for k=2, gives 2*3/2 = 3 . . . not 9
B) for k=1, gives 2^3/3 = 8/3 . . . not 1
C) for k=2, gives (2^2*3^2)/4 = 9 . . . . looks promising
D) for k=1, gives 1*2^3/5 = 8/5 . . . not 1

Selection C is the only viable choice. (And the correct one.)

6 0
3 years ago
if anyone could help me to figure out whether or not this is correct i would appreciate that. thank you :)
hram777 [196]
450 with an exponent of 3 equals -1425 so I think u are right
3 0
3 years ago
Read 2 more answers
IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s
butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are​ usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are​ usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 116, \sigma = 16

What are the z scores that separate the unusual IQ scores from those that are​ usual?

If Z<-2 or Z > 2, the IQ score is unusual.

So the z-scores that separate the unusual IQ scores from those that are​ usual are Z = -2 and Z = 2.

What are the IQ scores that separate the unusual IQ scores from those that are​ usual?

Those IQ scores are X when Z = -2 and X when Z = 2. So

Z = -2

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 116}{16}

X - 116 = -2*16

X = 84

Z = 2

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 116}{16}

X - 116 = 2*16

X = 148

The IQ scores that separate the unusual IQ scores from those that are​ usual are 84 and 148.

8 0
3 years ago
Read 2 more answers
27 x 26 x 28 x 34 x 45
andreev551 [17]

27 x 26 x 28 x 34 x 45 = 30,073,680

8 0
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