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Scrat [10]
3 years ago
7

If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer:

<em>B</em> (x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)

Step-by-step explanation:

<u>Dilations</u>

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

The y-coordinate of E is 2 and the y-coordinate of E' is 5. This gives us the same scale factor for the y-axis of 5/2.

Thus, the rule to dilate the pentagon is:

B \mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}

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Answer:

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We have 5 places here, and each place can have 4 options because repetition is allowed.

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We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

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<em>3. 3 digit numbers:</em>

We have 3 places here, and each place can have 4 options because repetition is allowed.

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We have <em>2</em> places here, and each place can have 4 options because repetition is allowed.

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4 \times 4 \\ \Rightarrow 16

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We have 1 place here, and each place can have 4 options because repetition is allowed.

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3 years ago
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