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Scrat [10]
3 years ago
7

If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?

Mathematics
1 answer:
svetlana [45]3 years ago
5 0

Answer:

<em>B</em> (x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)

Step-by-step explanation:

<u>Dilations</u>

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

The y-coordinate of E is 2 and the y-coordinate of E' is 5. This gives us the same scale factor for the y-axis of 5/2.

Thus, the rule to dilate the pentagon is:

B \mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}

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Ronch [10]

Answer:

the answer is A

Step-by-step explanation:

3 0
3 years ago
39x38 multiply using partial prodcuts
yKpoI14uk [10]
39 x 10
= 390

39 x 40 (390 x 4)
= 1,560

39 x 2
= 78

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= 1,482

ANSWER: 1,482
4 0
3 years ago
If the surface area of a cube is 294, whats the length of the cube?
tatyana61 [14]

Answer:

7

Step-by-step explanation:

Total number of surfaces of cube are 6.

Each surface is square.

And area of square is (side)^2

That means, total surface area will be 6 * (side)^2

From question,

294 = 6 * (side)^2 ( Surface area given)

=> 294 ÷ 6 = ( side) ^2

=> 49 = side^2

=> √49 = side

=> 7 = side

So, length of edge of cube is 7

7 0
3 years ago
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lisabon 2012 [21]
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5 0
3 years ago
A stone is launched into the air from a height of 240 feet. The height, h, of the stone, in feet, t seconds after launch is give
rosijanka [135]

A projectile is an object <u>launched</u> into space, and moving under the <em>influence</em> of <u>gravity</u> and <u>momentum</u>. The <em>stone</em> here is an example. Thus, the <em>time</em> taken for the stone to reach the ground is 10 seconds.

On <em>launching</em> of the stone into <u>space</u>, it behaves as a <u>projectile</u>. Thus moving under the <em>influence</em> of gravity and its momentum. Its <u>momentum</u> is the <em>product</em> of its <u>mass </u>and <u>velocity</u>.

The height h, is given as:

h = 16t^{2} + 32t + 240

Differentiating the expression with respect to t, we have;

32t + 32 = 0

t = -1 seconds

Substitute the value of time, t, in the equation for the height;

h = 16 - 32 + 240

  = 224

h = 224 m

Total height, S = 240 + 224

                         = 464

S = 464 m

The total height covered by the stone is 464 m.

From the second equation of <em>free fall</em>,

S = Ut + \frac{1}{2}gt^{2}

S = \frac{1}{2}gt^{2}

464 = \frac{1}{2}*9.8*t^{2}

t^{2} = \frac{928}{9.8}

  = 94.694

t = \sqrt{94.694}

 = 9.7311

t ≅ 10 seconds

The <em>time taken</em> for the stone to hit the ground is 10 seconds.

Thus option A is the required answer.

Visit: brainly.com/question/13834669

7 0
3 years ago
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