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jek_recluse [69]
3 years ago
11

Can anyone help me on this I would appreciate it

Mathematics
2 answers:
ella [17]3 years ago
6 0
Insee its finna be 14
kaheart [24]3 years ago
3 0

Answer:

14

Step-by-step explanation:

Triangle=180

180-90 (RA) = 90

90-41= 39

(2x+11)=39

2x=28

x=14

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x=-7

Step-by-step explanation:

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What are the restrictions on the domain (u*v)(x)
Zepler [3.9K]

Answer: x≠0 and x can not be any value for which u(x) = 2

Step-by-step explanation:

According to the question,

The domain of the function u = R - {0}

Thus if x is the element of the domain of the function u

Then , x ≠0

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Since, The domain of the function v = R - {2}

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3 years ago
Determine if this equation always, sometimes or never true. <br><br> 6(x + 1) = 2(5 + 3x)
Rina8888 [55]
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4 years ago
What is the slope-intercept form of linear equations?
lara31 [8.8K]

to get the equation of any straight line, we simply need two points off of it, let's use the points from the picture below.

(\stackrel{x_1}{8}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{12}-\underset{x_1}{8}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{8}) \\\\\\ y-3=\cfrac{1}{2}x-4\implies y=\cfrac{1}{2}x-1

if we already have the slope, and we can see the y-intercept on the table, then we can simply use the slopel-intercept form and plug both of them in.

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \begin{array}{|c|ll} \cline{1-1} slope\\ \cline{1-1} \cfrac{1}{2}\\ \cline{1-1} y-intercept&\\\cline{1-1} (0~~,~~-1)\\ \cline{1-1} \end{array}~\hfill y=\cfrac{1}{2}x-1

6 0
3 years ago
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