Question

A triangle has vertices A(-1, -2), and B(1, 2), and C(-2, 0). Line p is parallel to side AB and contains point C. Write an equation for line p. Find the slope of AB. Show your work.​

Answer 1

Answer:

y = 2x + 4

Step-by-step explanation:

To write the equation of line p, use the end points of AB in the slope formula. Since line p is parallel to AB, this will be the same slope.

$m = \frac{y_2 -y_1}{x_2-x_1} = \frac{2--2}{1--1} =\frac{4}{2} = 2$

Substitute m = 2 and the point C at (-2,0) into the point slope form of the line. Simplify to find the equation.

$y - y_1 = m(x-x_1)\\y - 0 = 2(x--2)\\y = 2(x+2)\\y = 2x + 4$