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mixer [17]
3 years ago
6

9) Order the fractions from least to greatest. 2 4 , 4 5 , 7 10 , 2 3 A) 2 4 , 7 10 , 2 3 , 4 5 B) 7 10 , 2 4 , 2 3 , 4 5 C) 2 4

, 2 3 , 7 10 , 4 5 D) 2 4 , 7 10 , 4 5 , 2 3
Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

C) \frac{2}{4}, \frac{2}{3}, \frac{7}{10}, \frac{4}{5}

Step-by-step explanation:

Given fractions:

\frac{2}{4}, \frac{4}{5}, \frac{7}{10},\frac{2}{3}

To arrange the fractions from least to greatest.

Solution:

In order to arrange the fractions from least to greatest, we need to make the denominators common by taking LCD.

LCD of 4,5,10,3 can be found using their multiples.

4= 4,8,12,16,20,24,28,32,36,40,.........60

5= 5,10,15,20,25,30,.........60

10= 10,20,30,40,50,60

3= 3,6,9..........................60

So, 60 is the LCD.

Making the denominators common by multiplying same numbers to numerator and denominator.

\frac{2}{4}=\frac{2\times 15}{4\times 15}=\frac{30}{60}

\frac{4}{5}=\frac{4\times12}{5\times 12}=\frac{48}{60}

\frac{7}{10}=\frac{7\times 6}{10\times 6}=\frac{42}{60}

\frac{2}{3}=\frac{2\times 20}{3\times 20}=\frac{40}{60}

Comparing the numerators we can arrange the fractions.

\frac{2}{4}, \frac{2}{3}, \frac{7}{10}, \frac{4}{5}

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Answer:

The tangent line to the given curve at the given point is y=9x-26.

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of y=2x^2-7x+6 and then evaluate it for x=4.

(y=2x^2-7x+6)'          Differentiate the equation.

(y)'=(2x^2-7x+6)'       Differentiate both sides.

y'=(2x^2)'-(7x)'+(6)'    Sum/Difference rule applied: (f(x)\pmg(x))'=f'(x)\pm g'(x)

y'=2(x^2)'-7(x)'+(6)'  Constant multiple rule applied: (cf)'=c(f)'

y'2(2x)-7(1)+(6)'        Applied power rule: (x^n)'=nx^{n-1}

y'=4x-7+0               Simplifying and apply constant rule: (c)'=0

y'=4x-7                    Simplify.

Evaluate y' for x=4:

y'=4(4)-7

y'=16-7

y'=9 is the slope of the tangent line.

Point slope form of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on the line.

Insert 9 for m and (4,10) for (x_1,y_1):

y-10=9(x-4)

The intended form is y=mx+b which means we are going need to distribute and solve for y.

Distribute:

y-10=9x-36

Add 10 on both sides:

y=9x-26

The tangent line to the given curve at the given point is y=9x-26.

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

\lim_{x \rightarrow 4}(2x+1)

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

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