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mixer [17]
3 years ago
6

9) Order the fractions from least to greatest. 2 4 , 4 5 , 7 10 , 2 3 A) 2 4 , 7 10 , 2 3 , 4 5 B) 7 10 , 2 4 , 2 3 , 4 5 C) 2 4

, 2 3 , 7 10 , 4 5 D) 2 4 , 7 10 , 4 5 , 2 3
Mathematics
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

C) \frac{2}{4}, \frac{2}{3}, \frac{7}{10}, \frac{4}{5}

Step-by-step explanation:

Given fractions:

\frac{2}{4}, \frac{4}{5}, \frac{7}{10},\frac{2}{3}

To arrange the fractions from least to greatest.

Solution:

In order to arrange the fractions from least to greatest, we need to make the denominators common by taking LCD.

LCD of 4,5,10,3 can be found using their multiples.

4= 4,8,12,16,20,24,28,32,36,40,.........60

5= 5,10,15,20,25,30,.........60

10= 10,20,30,40,50,60

3= 3,6,9..........................60

So, 60 is the LCD.

Making the denominators common by multiplying same numbers to numerator and denominator.

\frac{2}{4}=\frac{2\times 15}{4\times 15}=\frac{30}{60}

\frac{4}{5}=\frac{4\times12}{5\times 12}=\frac{48}{60}

\frac{7}{10}=\frac{7\times 6}{10\times 6}=\frac{42}{60}

\frac{2}{3}=\frac{2\times 20}{3\times 20}=\frac{40}{60}

Comparing the numerators we can arrange the fractions.

\frac{2}{4}, \frac{2}{3}, \frac{7}{10}, \frac{4}{5}

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Step-by-step explanation:

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Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

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Subtract 7 from both sides

x^2 - 6x - 7 = 7 - 7

Simplify

x^2 - 6x - 7 = 0


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The final solutions to the quadratic equation are:

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