increase the speed is definitely the answer
The length of each side of the larger square is 8 cm.
<u>Step-by-step explanation</u>:
Step 1 ;
- The combined area of two squares = 80 sq.cm
- The side of small square = x
- The side of larger square = 2x
Step 2 :
Area of the square = a^2
Area of small square + area of large square = 80
x^2 + (2x)^2 = 80
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 80/5
x^2 = 16
x = ±4
Step 3 :
Since length cannot be negative, the value of x= 4
∴ The length of the side of small square = 4cm
The length of the side of larger square = 2x = 8cm
Answer:
65 dm and 52 dm
Step-by-step explanation:
If the scale factor of the sides is k, then the scale factor of the areas is k^2.
The scale factor of the areas is (32 dm^2)/(50 dm^2) = 0.64 = k^2
The scale factor of the sides is k = \sqrt(0.64) = 0.8
The perimeters are in a ratio of 1:0.8
x + 0.8x = 117
1.8x = 117
x = 65
0.8x = 0.8(65) = 52
The perimeters are 65 dm and 52 dm.
Answer:
length, width, and height are (b+2), (b-2), (b+3)
Step-by-step explanation:
Doing what the problem statement tells you to do, you get ...
(b^3 +3b^2) -(4b +12)
= b^2(b +3) -4(b +3) . . . . . factor each pair of terms
= (b^2 -4)(b +3) . . . . . . . . . write as a product
= (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares
The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.
Step-by-step explanation:
<span>Answer is: 414 pounds of red fescue and 138 pounds of chewings fescue is needed to produce 552 pounds of mixture.</span>
<span>Explanation:
x - how much of red fescue is needed for one pound of mixture
y - how much of chewings fescue is needed for one pound of mixture</span>x*12+ y*16 = 15<span>x + y = 1
so, x=1-y
putting it into first line:</span><span>(1-y)*12 + y*16 = 15
12 - 12*y + 16*y = 15
4*y = 3
y=3/4
so, x= 1-3/4; x=1/4</span>So to produce 552 pounds of mixture we need..<span>To produce 1 pound of mixture we need: 3/4 pound of red fescue and 1/4 pound of chewing fescue so to produce 552 pounds of miture we need:
552*3/4 - red fescue, which is 414 pounds needed
and
552/4 - chewings fescue, which is 138 pounds needed</span>
