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3 years ago

13

True/False: An element of a two-dimensional array is referenced by the array name and two subscripts, first the element row numb

er and then the element column number.

1 answer:

MAVERICK [17]3 years ago

7 0

Answer:

This is true statement.

Step-by-step explanation:

The given statement is true.

We know that the first element of the array is a[0], the second element is a[1], and so on.

The subscript that specifies single elements of an array is an integer expression written/denoted in square brackets. The elements of a 2D array are arranged in rows and columns.

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Stacy goes to the county fair with her friends . The total cost of ride tickets is given by the equation c=3.5t , where c is the

madreJ [45]

Answer:

<h2><u>$52.5</u></h2>

Step-by-step explanation:

Step one:

given data

we are given that the linear function for the cost is c=3.5t

c is the cost and

t is the number of tickets.

We are told that t=15, to find c, let us put the value of t in the linear function for the cost

$c=3.5(15)\\\\c=52.5$

<u>This shows that 15 tickets will cost $52.5</u>

<u />

3 0

2 years ago

For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation c

Illusion [34]

Answer: Our required equation would be $6=\dfrac{c}{2}+1$

Step-by-step explanation:

Since we have given that

Amount that Anderson earns per hour = $6

According to question, Anderson earns $1 more than half of Carey's hourly rate.

Let the hourly rate of Carey be 'c'.

So, it becomes,

$6=\dfrac{c}{2}+1$

And the value of c would be

$6=\dfrac{c}{2}+1\\\\6-1=\dfrac{c}{2}\\\\5=\dfrac{c}{2}\\\\c=\$10$

Hence, our required equation would be $6=\dfrac{c}{2}+1$

5 0

3 years ago

Hi, Could anyone help me with my homework

tatiyna

Answer:

$\hookrightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

solving steps:

$\rightarrow \sf (x + 4)^6$

$\bold{rewrite \ the \ following}$

$\rightarrow \sf (x + 4)^2 (x + 4)^2 (x + 4)^2$

$\bold {formula \ used : \sf (x+a)^2 = (x^2 + 2xa + a^2)}$

$\rightarrow \sf (x^2 + 8x+16) (x^2 + 8x+16) (x^2 + 8x+16)$

$\bold{simplify \ by \ removing \ parenthesis}$

$\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)$

$\bold{basic \ addition \ of \ integers }$

$\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)$

$\bold{remove \ parenthesis}$

$\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)$

$\bold {final \ answer:}$

$\rightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

8 0

2 years ago

What is the mode of the following numbers?<br> 9, 10, 6, 5, 69,10,6,5,6

mash [69]

6 is the mode since it appears the most, 3 times

6 0

3 years ago

Read 2 more answers

We have seen that isosceles triangles have two sides of equal length. The angles opposite these sides have the same measure. Use

Naddik [55]

Question has missing figure, the figure is in the attachment.

Answer:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

Step-by-step explanation:

Given,

We have an isosceles triangle which we can named it as ΔABC.

In which Length of AB is equal to length of BC.

And also m∠B is equal to m∠C.

ext.m∠C= 115°(Here ext. stands for exterior)

We have to find the measure of angles angles 1 through 5.

Solution,

For ∠1.

∠1 and ext.∠C makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle1+ext.\angle C=180\°$

On putting the values, we get;

$\angle 1+115\°=180\°\\\\\angle1=180\[tex]\therefore m\angle2=65\°$ -115\°=65\°[/tex]

Thus the measure of ∠1 is 65°.

For ∠2.

Since the given triangle is an isosceles triangle.

So, $m\angle1=m\angle2$

Thus the measure of ∠2 is 65°.

For ∠3.

Here ∠1, ∠2 and ∠3 are the three angles of the triangle.

So we use the angle sum property of triangle, which states that;

"The sum of all the angles of a triangle is equal to 180°".

$\therefore \angle1+\angle2+\angle3=180\°$

Now we put the values and get;

$65\°+65\°+\angle3=180\°\\\\130\°+\angle3=180\°\\\\\angle3=180\°-130\°=50\°$

Thus the measure of ∠3 is 50°.

For ∠4.

∠4 and ∠2 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle2 +\angle 4 =180\°$

Substituting the values of of angle 2 to find angle 4 we get;

$65\°+ \angle 4 = 180\°\\\\ \angle 4 = 180\°-65\°\\\\\angle 4= 115\°$

Thus the measure of ∠4 is 115°.

For ∠5.

∠4 and ∠5 makes straight angle, and we know that the measure of straight angle is 180°.

So, we can frame this in equation form as;

$\angle4 +\angle 5 =180\°$

Substituting the values of of angle 4 to find angle 5 we get;

$115\°+ \angle 5 = 180\°\\\\ \angle 5 = 180\°-115\°\\\\\angle 5= 65\°$

Thus the measure of ∠5 is 65°.

Hence:

The measure of ∠1 is 65°.

The measure of ∠2 is 65°.

The measure of ∠3 is 50°.

The measure of ∠4 is 115°.

The measure of ∠5 is 65°.

6 0

2 years ago