What you want is P(6∩1) or P(1∩6) or P(2∩5) or P(5∩2) or P(3∩4) or P(4∩3).
The events of rolling the dice are independent (i.e. they don't affect one another) so:
E.g.
P(6∩1) = P(6) * P(1)
P(2∩5) = P(2) * P(5)
The probability of getting a given number on a roll is 1/6 for both dice.
So:
P(6∩1) = 1/6 * 1/6 = 1/36
This is the same for any arrangement of numbers you could get from rolling two dice.
So, we can see that there are 6 arrangements of numbers that will give a sum of 7 and so that is 6 * 1/36 = 6/36 = 1/6
Answer:To plot the point you would start with -1 so you would go to the left till you reach -1 then to plot -2 you would go DOWN till you reach -2 Detail:the first number is ALWAYS how many times you go left or right the second number determine if you go up or down and negatives are always left and down and positive are always right and up unless you have 1,-5 then it’s to the right down and if you have -5, 7 you go left and up :3 hope this helps
Answer:
Union of inqualities:
x<7 or x>8
(not sure if this helps or not sorry!)
Ambiguous expression. I think you meant:
3x + 7
<span>3x/(x+5)+7/(x+5) = --------------
x+5
There's no "answer." All you can do here is to combine the terms and simpify the resulting sum.
</span>
H(t) = t^(3/4) - 3t^(1/4)
The critical points can be evaluated by taking the first derivative and equating to 0.
h'(t) = 3 / t^(1/4) - 3 / 4t^(3/4)
3 / (4t^(3/4)) = 3 / t^(1/4)
4t^(3/4) = t^(1/4)
4 = 1/√t
t = 1/16, t = -1/16
