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sammy [17]
3 years ago
14

(−3y ​2 ​​ −5y−2)+(−7y ​2 ​​ +5y+2)= Standard form please

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

-10y^2

Step-by-step explanation:

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5 0
3 years ago
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Which of the following represents the general term for the sequence 1, 3, 5, 7, 9, . . .? n
zalisa [80]

Answer:

Step-by-step explanation:

In the given sequence, the terms are increasing in arithmetic progression. The common difference, d between successive terms is 2

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 1

d = 2

Therefore, the expression for the general term for the sequence is

Tn = 1 + 2(n - 1)

3 0
3 years ago
Li-Ming owns an ice cream shop. On Saturday evening from 6:00 PM to 7:00 PM, 80 people entered her shop. On Tuesday from 3:00 PM
KengaRu [80]
To find the percent decrease from Saturday to Tuesday, you will find the difference between the number of customers on those days and divided by the total number of customers on Saturday.

By dividing this you will get a decimal, which then can be converted to a percent.

80-17= 63

63/80 = 0.7875
0.7875 = 78.75%

There was a 78.75% decrease from Saturday to Tuesday.
6 0
3 years ago
Order the following numbers from least to greatest.<br><br> 0.303, 0.3, 0.033, and 0.33
nlexa [21]

Answer:

0.033, 0.3, 0.303, 0.33

Step-by-step explanation:

0.033

0.3 = 0.300

0.303

0.33 = 0.330

if you ignore the 0. then it is like working with whole numbers :)

3 0
3 years ago
The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds
Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 200, \sigma = 50

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

Z = \frac{X - \mu}{\sigma}

Z = \frac{220 - 200}{50}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 170

Z = \frac{X - \mu}{\sigma}

Z = \frac{170 - 200}{50}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0
4 years ago
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