PLEASE ANSWER + BRAINLIEST!!

In the diagram, BC¯¯¯¯¯∥DE¯¯¯¯¯ . What is AE ?

emmainna [20.7K]

So there are two triangles here: Smaller one (ADE) and bigger one (ABC) and they both are similar.

So you can use proportions here.

AB / AC = AD / AE

AB = AD + DB = 6 + 1 = 7
AC = AE + 3

AD = 6

So plug in these values:

AB / AC = AD / AE becomes
7 / (AE + 3) = 6 / AE

Now do the cross multiply:

7 AE = 6 (AE + 3)

Now solve for AE:

7AE = 6AE + 18

AE = 18

6 0

2 years ago

The simple interest on a sum of money for 2 years at 12% per annum is rupees 1380

julia-pushkina [17]

Answer:

5750

710.7

Step-by-step explanation:

Simple interest = principal. * rate * time

Principal (p) = sum of money

1380 = p * 0.12 * 2

1380 = 0.24p

p = 1380 / 0.24

p = 5750 rupees.

The compound interest :

A = P(1 + r/n)^nt

A = final amount

n = number of compounding times per period

t = period

A = 5750(1 + 0.12/2)^2*1

A = 5750(1 + 0.06)^2

A = 5750(1.06)^2

A = 5750 * 1.1236

A = 6460.7

Hence, compound interest is :

Final amount - principal

6460.7 - 5750

= 710.7 rupees

4 0

3 years ago

Please help with geometry. 20 points, and another question worth 98 on my profile!

vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) $PR^{2} =PS*PT$

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The Intersecting Secant-Tangent Theorem, states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

$PR^{2} =PS*PT$

Part 3)

we know that

The Tangent-Tangent Theorem states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0

2 years ago

Zach is 4 years older than twice his sister maya’s age. maya is 5 years old. how old is zach?

SCORPION-xisa [38]

Zach is 14 bc...
-4 years older(+4) than twice (x2) Mayas age.
-Maya is 5
- the correct order is 5x2+4
-5x2=10, 10+4=14

4 0

2 years ago

received a bag of his favorite candies, for Teacher Appreciation Week, 5 were Hersey's, 3 were Butterfingers, 7 were crunched, a

dlinn [17]

Answer:i dont know

ok

i just need points

Step-by-step explanation:

done ??

3 0

2 years ago