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aalyn [17]
3 years ago
15

I have a math question I need help answering.

Mathematics
1 answer:
aniked [119]3 years ago
6 0
The answer should be $21,840.50

Explanation:

20000*1.045=a (first year)
a*1.045=b (second year)
b = 21840.5
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-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




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If the average of 3 numbers and 8 is 25 what is the sum of the three numbers
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Let sum of 3 numbers be x.

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25 = \frac{x +8}{4}

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The sum of 3 numbers is 92.


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Step-by-step explanation:

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