Answer:
Final answer is ![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
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Step-by-step explanation:
Given problem is ![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
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Now we need to simplify this problem.
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
Hence final answer is .
Step-by-step explanation:
f(3)=?
f(x)=2x+5
put x=3,
f(3)=2(3)+5=6+5=11
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g(2)=?
g(x)=x^2-3
put x=2,
g(2)=2^2-3=4-3=1
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g(f(-1))=?
g(x)=x^2-3
and f(-1)=2(-1)+5= -2+5=3
so g(f(-1))=3^2-3=9-3=6
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f(g(-1))=?
f(x)=2x+5
g(x)=g(-1)=(-1)^2-3=1-3= -2
f(g(-1))=2(-2)+5= -4+5=1
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g(f(x))=?
g(x)= x^2-3
put x=f(x),
g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25
I would say, the best way and the fastest way, is to go to some banks and ask them how much interests they give you... then the bank that gives you the most interest, the bank that you are looking for.
Answer: i think it's (-4,-10)=m
Step-by-step explanation:
