Answer:
It's hard to make out which is x and y, if x is lower right and y is at the top, then:
x = 55°
y = 70°
Step-by-step explanation:
x = 55° because it is an isosceles triangle
y = 180° - 55° - 55° = 70°
D.only lines p, q, and r are parallel to each other
Answer:
Noah needs 8 pounds of the coffee that costs $9.20 per pound and 12 pounds of the coffee that costs $5.50 per pounds
Step-by-step explanation:
Let the number of pounds of the coffee that sells for 9.20 be x while the number of pounds of the coffee that sells for 5.5 be y.
From the question, we know he wants to make 20 pounds of coffee
Thus;
x + y = 20 •••••••••••(i)
Let’s now work with the values
For the $9.20 per pound coffee, the cost out of the total will be 9.20 * x = $9.20x
For the $5.5 per pound coffee, the cost out of the total be 5.5 * y = $5.5y
The total cost is 20 pounds at $6.98 per pound: that would be 20 * 6.98 = $139.6
Thus by adding the two costs together we have a total of $139.6
So we have our second equation;
9.2x + 5.5y = 139.6 •••••••(ii)
From i, y = 20 - x
Let’s substitute this in ii
9.2x + 5.5(20-x) = 139.6
9.2x + 110 -5.5x = 139.6
9.2x -5.5x = 139.6-110
3.7x = 29.6
x = 29.6/3.7
x = 8 pounds
Recall;
y = 20 - x
y = 20-8
y = 12 pounds
Answer:
$41.33
Step-by-step explanation:
Let the money be x
Game cost = 2/3*x
balance= 1/3*x
x/3= 15.5
Solve for x
x= 15.5*3
x=$46.5
so his money was $46.5
Amount spent on Game
=2/3*46.5
=$31
He spent 2/3 of 15.5 on Jacket
=2/3*15.5
=$10.33
In all he spent =31+10.33 =$41.33
Answer:
To calculate the volume of a sphere, use the formula v = ⁴⁄₃πr³, where r is the radius of the sphere. If you don't have the radius, you can find it by dividing the diameter by 2. Once you have the radius, plug it into the formula and solve to find the volume.
Step-by-step explanation:
To find the volume of a soccer ball,the formula is V=4/3 πr^3,where r is the radius and π=3.14. A regulation soccer ball has a radius of 35cm. find the volume of a soccer ball to the nearest cubic centimeter. This is just some to keep in mind.
