An expression for the height of the nth bounce is 0.80X^N = Height.
<h3><u>Equations</u></h3>
Since when dropped, a super ball will bounce back to 80% of its peak height, continuing on in this way for each bounce, to determine an expression for the height of the nth bounce the following calculation must be performed:
- X = Initial value
- 80% = 0.80
- N = Number of times the ball bounces
- 0.80X^N = Height
Therefore, an expression for the height of the nth bounce is 0.80X^N = Height.
Learn more about equations in brainly.com/question/2263981
Answer:
314
Step-by-step explanation:
First, find the diameter which is 10 and square it. Then, multiply by pi or 3.14 to get 314.
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Answer:
It should be y=4x-7
Step-by-step explanation:
M is the slope meaning Δx over Δy or rise over run
So if you look at (2,2) and count up to (3,6) the rise is 4 and the run is 1 meaning the slope is 4.
B is the y- intercept so then it would just be -7.
To get the Greates Common Factor (GCF) of 72 and 200 we need to
factor each value first and then we choose all the copies of factors and
multiply them:
<span><span>72: 22233 </span><span>200: 222 55</span><span>GCF: 222 </span></span>
The Greatest Common Factor (GCF) is: 2 x 2 x 2 = 8
Answer: 8
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
